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Rus_ich [418]
3 years ago
15

Find the length of an arc made by a 180-degree central angle in a circle with a 10ft radius

Mathematics
1 answer:
mixas84 [53]3 years ago
8 0

Answer:

the length of an arc = 10π ft.

Step-by-step explanation:

The length of an arc with angle Θ and radius r will be equal r * Θ

note the angle must be in radian

Given: Θ = 180° = π  and radius = r = 10 ft.

<u>So, the length of the arc = π * 10 = 10π ft.</u>

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You run one lap around a mile track every 8 minuets. Your friend runs around the same track every 10 minutes. You both start at
GalinKa [24]
So 8x5=40 and 10×4=40 so you and your friend meet at the 40 th min
6 0
3 years ago
Need help on quiz plz
malfutka [58]

Answer:

x = 34 degrees

Step-by-step explanation:

Each solid line and triangle add up to 180, so start from the left and slowly do your math.

180 - 112 = 68

180 - 68 - 43 = 69

180 - 69 = 111

180 - 111 - 35 = 34

x and the last angle are the same.

8 0
3 years ago
What is the equation of the line that passes through the point (2,-1) and has a slope of 3/2
Assoli18 [71]

Answer:

y=3/2x-4

Step-by-step explanation:

y=3/2x+b

-1=3/2(2)+b

-1=3+b

-4=b

y=3/2x-4

5 0
2 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
A gym charges a one time sign-up fee of $10.25 and then $5 each time you go. A student paid a total of $137.25. How many times d
horrorfan [7]

Answer:

25.4 or 25 times

Step-by-step explanation:

137.25-10.25=127

127/5=25.4

4 0
3 years ago
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