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3 years ago

Find the length of an arc made by a 180-degree central angle in a circle with a 10ft radius

Mathematics

1 answer:

mixas84 [53]3 years ago

8 0

Answer:

the length of an arc = 10π ft.

Step-by-step explanation:

The length of an arc with angle Θ and radius r will be equal r * Θ

note the angle must be in radian

Given: Θ = 180° = π and radius = r = 10 ft.

<u>So, the length of the arc = π * 10 = 10π ft.</u>

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Which ordered pair is the solution to the system of equations? {y=x−4−4x+3y=−3 (−9, −13)

Leviafan [203]

The correct answer is (-9, -13)

p.s I already took the test and this was right
hope I helped :)

8 0

3 years ago

Use the Normal model N(1133,78) for the weights of steers.

Rudiy27

Answer:

Step-by-step explanation:

Let $X\sim N(1133, 78)$ .

Here, the mean is 1133 and standard deviation is 78.

Since we don't have the table for N(1133, 78), so we use the standard table for N(0,1),

All we have to do is find, within the table the specific percentile.

now to find (42nd percentile) 0.42 in the normal table N(0,1) and extract the number on the row and column.

$P(X\leq x)=0.42$

Using: $Z=\frac{X-\mu}{\sigma}$ where $\mu$ is the mean and $\sigma$ is the standard deviation.

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.42$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.42$

Now, using Standard Normal table to find the value of z- score;

Usually, tables are set up as the probability that a number, z is less than or equal to Z.

i.e, $z= -0.20$

Now, putting this value in $z=\frac{x-1133}{78}$ , to find x;

$\frac{x-1133}{78}=-0.20$

On Simplify, we get;

$x=1,117.4$ pounds

Similarly, find the weight for 91st percentile.

Follow the same steps that we have done in part (a),

$P(X\leq x)=0.91$ or

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.91$

⇒ $P(Z \leq \frac{x-1133}{78})=0.91$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.91$

Now, use normal table value to find the z-score;

Usually, tables are set up as the probability that a number, z is less than or equal to Z

we have, z= 1.34

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=1.34$

On simplify, we get

x= 1,237.52 pounds

the interquartile range (IQR)=3rd Quartile - 1st quartile

First find the 1st quartile:

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.25$

⇒ $P(Z \leq \frac{x-1133}{78})=0.25$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.25$

Now, we use normal table to find that z=-0.675

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=-0.675$

On simplify, we get

x= 1,080.35 pounds

Similarly, for third quartile

By symmetry z=0.675

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=0.675$

On simplify, we get

x= 1,185.65 pounds

then, IQR = 1185.65 -1080.35=105.3 pounds

7 0

3 years ago

Evaluate the expression 34 ÷ (14 − 5) × 2. (4 points)

GalinKa [24]

7.55 would be your answer

8 0

3 years ago

Read 2 more answers

The point (12,5) is on the graph.

sukhopar [10]

Answer:

put the dot on the graph and then move the x-coordinate by 1 spot

Step-by-step explanation:

5 0

3 years ago

Value mart is having a back to school sale on pencils a pack of 30 sells for 7.97 whereas a 12 pack brand cost for 4.77 which is

wolverine [178]

30 pack.

if you buy 2 12 packs, it will cost 9.54 and that's only 24 pencils.

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3 years ago