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3 years ago

TRUE OR FALSE becomes zero for x=1PLEASE HELP

Mathematics

1 answer:

dem82 [27]3 years ago

5 0

Answer:

False

Step-by-step explanation:

x is 1 not zero

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What value of x makes the horizontal parts of the letter Z parallel?

Olenka [21]

Answer:

20 degrees

Step-by-step explanation:

in order for them to be parallel, the alternate interior angles must be congruent

x+20=2x

therefore x=20

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3 years ago

I’m confused on this one

ad-work [718]

The question is "What is the scale of the model to the actual statue"

That means you must put 2/15.

2 being the model

15 being the actual statue

Take that fraction and equal is to 1/x.

Multiply 15 to 1 and 2 to x.

In the end, to solve, you divide 15 by 2x.

The answer is X=7.5

1 : 7.5

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3 years ago

What is 2 3/4 - 5/16

Ilya [14]

Answer:

2 7/16

Step-by-step explanation:

multiply both top and bottom of 2 3/4 to make it 12/16 then subtract from there.

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3 years ago

Read 2 more answers

Graph the function. g(x)=1/3(x-6)^2+1

sladkih [1.3K]

Step-by-step explanation:

g(x)=1/3(x-6)^2+1

The graph of this function is in the attachment

3 0

3 years ago

For each function, y varies directly with x. Find each constant of variation. Then find the value of y when x=-0.3

Viktor [21]

Answer:

1- The constant of variation is $\frac{10}{3}$

2- The constant of variation is $\frac{4}{3}$

Explanation:

When two variables are in direct variation, this means that when one of them increases, the other increases and vice versa

A direct variation relation is represented as follows:

y = kx

where k is the constant of variation

Now, to get the constant of variation, all we have to do is substitute with the given x and y variables and solve for k

For the given problems:

1- $y = \frac{2}{3}\ when\ x=0.2$ 

Therefore:

$y = kx\\\\\frac{2}{3} = 0.2k\\\\ k = \frac{10}{3}$

2- $y = 4\ when\ x=3$ 

Therefore:

$y = kx\\ 4 = 3k\\ k = \frac{4}{3}$

Hope this helps :)

5 0

3 years ago

TRUE OR FALSE becomes zero for x=1PLEASE HELP​​

TRUE OR FALSE becomes zero for x=1PLEASE HELP