A = 1/3 * s^2 * h where s is a side of the base and h is the height.
Answer:
t = -24*log(2/3)
Step-by-step explanation:
The expression is:
V = 22,500*10^(-t/12)
Replacing with V = 10,000 and isolating t, we get:
10,000 = 22,500*10^(-t/12)
10,000/22,500 = 10^(-t/12)
4/9 = 10^(-t/12)
(2/3)² = 10^(-t/12)
2*log(2/3) = -t/12
-12*2*log(2/3) = t
t = -24*log(2/3)
we are given
system of equations
First equation is

Second equation is

now, we can find augmented matrix

now, we can change it into reduced row echelon form
step-1: multiply the 1st row by 1/3

step-2:add -3 times the 1st row to the 2nd row

step-3:multiply the 2nd row by 1/4

step-4: add 2/3 times the 2nd row to the 1st row

so, we get

Answer is (5,-8)
Answer:
StartFraction 24 Over 65 EndFraction
Step-by-step explanation:
Total number of students = 26
Number of boys = 10
Number of girls = 26-10
=16
Eduardo has to pull two names out of the hat without replacing them.
First name
Probability= Favourable outcome/Total outcome
Probability of girls=16
Total probability=26
Eduardo has to pull two names out of the hat without replacing them.
Probability= Favourable outcome/Total outcome
=16/26
=8/13
For the second name:
Without replacement of the first hat
Probability of girls=16-1=15
Total probability=26-1=25
Probability= Favourable outcome/Total outcome
=15/25
=3/5
Probability of both of Eduardo's partner for the group project will be girls=8/13*3/5
=24/65
StartFraction 24 Over 65 EndFraction