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CaHeK987 [17]
3 years ago
12

N a game, four cards are labeled N, S, E, and W. Two tiles are numbered 1 and 2. Two discs are red and blue. A player randomly s

elects one card, one tile, and one disc. Find the probability the player selects a card with S or E, a tile with 2, and a red disc.
Mathematics
1 answer:
algol [13]3 years ago
5 0

Answer: The probability that the player selects a card with S or E, a tile with 2 and a red disc is given as 0.125 (or 1/8)

Step-by-step explanation: If four cards are labelled N, S, E and W, then that means there are a total of four possible outcomes. Also with tiles numbered 1 and 2 there are a total of two possible outcomes when selecting tiles. Then there are two discs in total (one red and one blue) which means there are a total of two outcomes when selecting discs.

To select a card with S would be calculated as follows;

P(S) = Number of required outcomes/Number of all possible outcomes

P(S) = 1/4

P(S) = 0.25

To select a card with E would likewise be calculated as follows;

P(E) = Number of required outcomes/Number of possible outcomes

P(E) = 1/4

P(E) = 0.25

Therefore, the probability that a player selects a card with S or E is derived as follows;

P(S or E) = P(S) + P(E)

P(S or E) = 0.25 + 0.25

P(S or E) = 0.5

The probability that he selects a tile with 2 written on it is calculated as;

P(T2) = Number of required outcomes/Number of all possible outcomes

P(T2) = 1/2

P(T2) = 0.5

The probability that he will select a red disc is calculated as;

P(R) = Number of required outcomes/Number of possible outcomes

P(R) = 1/2

P(R) = 0.5

Therefore, the probability that the player selects a card with S or E, a tile with 2 and a red disc is calculated as;

P(S or E and T2 and R) = 0.5*0.5*0.5

P(S or E and T2 and R) = 0.125

Hence the probability that the player selects a card with S or E, a tile with 2 and a red disc is 0.125 (or 1/8).

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jolli1 [7]

Answer:

30 units squared

Step-by-step explanation:

1/2(base)(height)

base=10

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1/2(10)(6) = 5*6 = 30!

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3 years ago
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Ksju [112]

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4 0
3 years ago
Write an equation of the line that passes through (−1,3) and is parallel to the line y=2x+2.
MA_775_DIABLO [31]

The equation of the line that passes through (−1,3) and is parallel to the line y = 2x + 2 in slope intercept form is y = 2x + 5

<h3><u>Solution</u>:</h3>

Given that line passes through (-1, 3) and parallel to line y = 2x + 2

We have to find the equation of the line

Let us first find the slope of the line

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c  ---- eqn 1

where "m" is the slope of the line and "c" is the y-intercept

Comparing the given line equation y = 2x + 2 with y = mx + c,

We get slope "m" = 2

The slope of parallel lines are equal

Hence slope of the line which is parallel to y = 2x + 2 is also 2

Now let us find the equation of line with slope "m" = 2 and passes through point (-1, 3)

Substitute (x, y) = (-1, 3) in eqn 1 to find value of "c"

3 = 2(-1) + c

3 = -2 + c

c = 5

Now substitute "c" = 5 and m = 2 in eqn 1 to get equation of required line

y = 2x + 5

Thus the equation of line in slope intercept form is y = 2x + 5

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B

Step-by-step explanation:

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V = length × width × height

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Q → V = 8 × 4 × 5 = 60 ft³

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What is the surface area?
mash [69]

\large\bf{\underline{Answer:}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{ = 3000 \:ft^2}

__________________________________________

\large\bf{\underline{Given:}}

  • A 3 dimensional figure with 5 sides
  • it has 3 rectangles with dimensions 28 ft and 25 ft
  • And 2 triangles with base =30 ft and height = 20 ft

\large\bf{\underline{To\: find:}}

  • Total surface area of figure

\large\bf{\underline{Therefore:}}

\bf{area \:of\: figure}

‎ㅤ{\bf = area \:of \:3\: rectangles + 2 \: triangles}

\large\bf{\underline{Formulas:}}

\boxed{\bf\pink{area\:of\: triangle= \frac{1}{2}\times base\times height}}

\boxed{\bf\pink{area\:of\: rectangle=length\times breadth}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3\times (28 \times 25 )+ 2(\frac{1}{2} \times 30 \times 20)}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3 \times 800 + 2 \times 300}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=2400+ 600}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3000}

__________________________________________

\large\bf{\underline{Hence,}}

❒ Area of given figure

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\huge\mathfrak{= 3000\: ft^2}

5 0
3 years ago
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