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Hunter-Best [27]
3 years ago
12

When 12 marbles are added to a rectangular aquarium, the water in the aquarium rises 1 1/2 inches. In total, how many marbles mu

st be added to the aquarium to raise the water 2 3/4 inches?
Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:21 marbles would be added to raise the water 2 3/4 inches

Step-by-step explanation:

When 12 marbles are added to a rectangular aquarium, the water in the aquarium rises 1 1/2 inches. Converting 1 1/2 inches to improper fraction, it becomes 3/2 inches

Let x represent the number of marbles that would be added to the aquarium to raise the water 2 3/4 inches. Converting 2 3/4 inches to improper fraction, it becomes 11/4 inches. Therefore

12 marbles = 3/2 inches rise

x marbles = 11/4 inches rise

Cross multiplying,

12 × 11/4 = 3/2 × x

33 = 3x/2

3x = 33 × 2 = 66

x = 66/3 = 21

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The variable q represents a positive integer. Does 3(59 + 9) + 5q represent a number that is greater than, less than, or equal t
hjlf

Answer:

Depends on the value of q.

Step-by-step explanation:

3(59+9) + 5q = 3(68) + 5q = 204 + 5q

4(59+6) = 260

7 0
2 years ago
Water level in a well was 20m below ground level. During rainy season, rainwater collected in different water tanks was drained
IgorC [24]

Answer:

17 m

Step-by-step explanation:

As shown in the figure,  A_0-B_0 is the ground level, A_1-B_1 is the old level of water which was at 20 m below ground level, A_2-B_2 is the new level of water which is 5m above of old level. The height of wall of the well, 1.20 m, and the the pelly at 80 cm =0.80 m, has been shown too.

The minimum length of the rope is equal to the distance between the pully and the new water level, indicated by the length L_0 in the figure.

So, L_0= 20-5+1.20+0.80= 17m

Hence, Raghu must use a rope having the minimum length 17 m to draw water from the well.

6 0
3 years ago
What is the answer to 2 5/3-2 3/2=
jek_recluse [69]
First, we can convert both of them to improper fractions.

We do that by multiplying the denominator to the whole number, adding it to the numerator, and keeping the denominator.

2 5/3 - 2 3/2

So we have:

11/3 - 7/2

Convert both of them to denominators of 6:

22/6 - 21/6

Subtract the numerators and keep the denominators:

1/6
3 0
3 years ago
Read 2 more answers
Measuring and arcs.
n200080 [17]

Answer:

Hope this helps

Step-by-step explanation:

3. Minor arc, 44°

4. Major arc, 140°

5. Minor arc, 44°

6. Major arc, 316°

7. Semi circle, 180°

8. Major arc, 140°

9. 38°

10. 52°

11. 142°

12. 128°

13. 232°

14. 308°

7 0
3 years ago
A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as
mamaluj [8]

Answer:

The farmer have at first <u>202</u> chickens.

Step-by-step explanation:

Given:

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as ducks left.

Now, to find the chickens farmer have at first.

Let the chickens be x.

And, the ducks be y.

<em>As, the farmer had twice as many chickens as ducks on his farm.</em>

So, x=2y    ......(1)

<em>As, given the farmer after selling 166 chickens and ducks, he had half as many chickens as ducks left.</em>

According to question:

x-166=(y-29)\times \frac{1}{2}

x-166=\frac{y-29}{2}

Substituting the value of x from equation (1) we get:

2y-166=\frac{y-29}{2}

<em>By cross multiplying we get:</em>

4y-332=y-29

<em>Adding both sides 332 we get:</em>

4y=y+303

<em>Subtracting both sides by </em>y<em> we get:</em>

3y=303

<em>Dividing both sides by 3 we get:</em>

y=101.

Now, to get the number of chickens substituting the value of y in equation (1):

x=2y\\\\x=2\times 101\\\\x=202.

Therefore, the farmer have at first 202 chickens.

7 0
3 years ago
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