Help me please? 15 points to anyone who can help me!"Find the number of permutations of the first nine letters of the alphabet t

aking six letters at a time."

Mathematics

1 answer:

gladu [14]3 years ago

7 0

$_{9}P_{6}=\frac{9!}{(9-6)!}=\frac{9!}{3!}=\frac{362,880}{6}=60,480$

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Might have to experiment a bit to choose the right answer.

In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.

Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456

In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
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