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Jet001 [13]
3 years ago
9

5.

Mathematics
1 answer:
puteri [66]3 years ago
5 0
 <span>1C. 5^3 = 125 mL 
2A. 30^3 = 27,000 mL = 27 L 
3D. 75 mm is 7.5 cm, so we do: 7.5^3 = 421.875 mL = 0.421875 L =~ 0.422 L 

Note: 
1 mL = 1 cm^3 
1 L = 1,000 mL 
10 mm = 1 cm</span>
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9) 6a² + 3 = 435<br> How to solve this equation by taking square root?
WITCHER [35]

6a² + 3 = 435

First subtract 3 from both sides:

6a^2 = 432

Divide both sides by 6:

a^2 = 432/6

a^2 = 72

Now take the square root of both sides to get a:

a = √72  

5 0
4 years ago
What is the solution to the compound inequality 5x + 7 &gt; −8 and 3x + 7 ≤ 19?
Cerrena [4.2K]
Solve each

5x+7>-8
minus 7 both sides
5x>-15
divide by 5
x>-3

3x+7≤19
minus 7 both sides
3x≤12
divide by 3
x≤4


so we got
x>-3 AND x≤4
and means that the solution set must satisfy both at once
so x is bigger than -3 and less than or equal to 4
so between -3 and 4 including 4
-3<x≤4

last one
3 0
3 years ago
Q: Resolve in factors abc - ab - c + 1​
Kazeer [188]
Abc - ab - c + 1
=ab(c - 1) - (c - 1)
= (c - 1) (ab - 1)
7 0
3 years ago
At a pumpkin patch, if Armando guesses the weight of his pumpkin within 0.3 pounds, he gets to take the pumpkin home for free. I
Reil [10]

Answer: last option

Step-by-step explanation:

You know that the weight of his pumpkin 4.9 pounds and that, if he guesses its weight within 0.3 pounds, he will get the pumpkin for free.

Then, to find the minimum weight he can guess  in order to get his pumpkin for free, it's necessary to write the expression:

x-0.3=4.9

Rewriting it:

x-4.9=0.3

To find the maximum weight he can guess  in order to get his pumpkin for free, it's necessary to write the expression:

x+0.3=4.9

Rewriting it:

x-4.9=-0.3

7 0
3 years ago
Read 2 more answers
Find f (x )if f apostrophe apostrophe (x )equals x to the power of negative 2 end exponent comma space x greater than 0 comma sp
viva [34]

Step-by-step explanation:

Given g'(x) = g^{-2}, x> 0\ g(1) = 0 \ and \ g(2) = 0

To get g(x), we will have to integrate g'(x)

g(x)  = \int\limits {x^{-2}} \, dx\\ g(x)  = \frac{x^{-2+1}}{-2+1} + C\\ g(x) = -x^{-1} + C\\g(x) = -x^{-1} + C\\

If g(1) = 0, this means at x = 1, g(x) = 0

0 = -1⁻¹ + C

C= 1

Substitute C = 1 into the function

g(x) = -x⁻¹ + 1

If g(2) = 0, this means at x = 2, g(x) = 0

0 = -2⁻¹ + C

C= 2⁻¹

C =  1/2

Substitute C = 2 into the function

g(x) = -x⁻¹ + 1/2

3 0
3 years ago
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