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4 years ago

Can someone please help me on this?

Mathematics

1 answer:

Dmitry_Shevchenko [17]4 years ago

6 0

Answer:

In the Pythagorean theorem the two shortest sides must always be substituted for the side legs, not the hypotenuse

Step-by-step explanation:

Have a blessed day

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What is the volume of this cone? Use 3.14 for pi and round your answer to the

emmasim [6.3K]

So I use the formula hopefully these steps work

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2 years ago

Salma made 378 for 18 hours of work.

sammy [17]

Answer:

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Step-by-step explanation:

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3 years ago

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

Put $(x,y)=(1,1)$

$\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9$

This is true.

So, the point $(1,1)$ satisfies the equation $\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

So, point H is $(1,1)$ .

7 0

3 years ago

Look at the table showing different prices for oranges.

MrMuchimi

2.25 for 6 would be 0.375 per one of them
1.30 for 4 would be 0.325 per one of them
0.97 for 2 would be 0.485 per one of them

5 0

3 years ago

Read 2 more answers

Which is not a correct way to rewrite this expression using the distributive

Effectus [21]

Given:

The expression is

$(2x^2+4x-7)(x-2)$

To find:

The expression which is not a correct way to rewrite the given expression.

Solution:

We have,

$(2x^2+4x-7)(x-2)$

Using distributive property, we get

$=(2x^2)(x-2)+(4x)(x-2)+(-7)(x-2)$

$=(2x^2)(x)+(2x^2)(-2)+(4x)(x)+(4x)(-2)+(-7)(x)+(-7)(-2)$

Using distributive property the given expression can rewritten as:

$=(2x^2+4x-7)(x)+(2x^2+4x-7)(-2)$

Only the expression in option A is not a correct way to rewrite the given expression because $(2x^2+4x-7)$ is not distributed to $(x-2)$ properly.

Therefore, the correct option is A.

3 0

3 years ago