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adoni [48]
3 years ago
14

If the value of the feedback resistor in the filter is changed but the value of the resistor in the forward path is unchanged, w

hat characteristic of the filter is changed?
Engineering
1 answer:
Sholpan [36]3 years ago
6 0

Answer:

The cut off frequency and the  passband gain will change

Explanation:

Answer :

Since the cut off frequency ω and the passband gain K are the function of the feedback of the resistor R2, Both K  and ω will change.

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What is the saturation pressure, Vf, and Vg for saturated water at a temperature of 287 °C?
Dvinal [7]

Answer:

Vf = specific volume of saturated liquid  = 0.0217158 ft^3/lb

Vg = specific volume of saturated steam = 0.430129 ft^3/lb

Explanation:

Given data:

water temperature is given as 287-degree Celcius

we have to find Vf and Vg

Vf = specific volume of saturated liquid  

Vg = specific volume of saturated steam

we know that from the saturated steam table we can find these value

therefore for temperature 287-degree Celcius

Vf = specific volume of saturated liquid  = 0.0217158 ft^3/lb

Vg = specific volume of saturated steam = 0.430129 ft^3/lb

6 0
3 years ago
Info security:
il63 [147K]

Answer:

True

Explanation:

Dual home host - it is referred to as the firewall that is incorporated with two or more networks. out of these two networks, one is assigned to the internal network and the other is for the network. The main purpose of the dual-homed host is to ensure that no Internet protocol traffic is induced between both the network.

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7 0
4 years ago
A scale model is 4th the size of the pump. Determine the power ratio of the pump and its scale model if the ratio of the heads i
vredina [299]

Given:

size of scale model = 4(size of pump)

power ratio of pump and scale model = 5:1

Solution:

Let the diameter of scale model and pump be d_{s} and d_{p} respectively

and head be  H_{s} and  H_{p} respectively

Now, power, P is given as a function of head(H) and dischagre(Q)

P = \rho gQH                  (1)

From eqn (1):

P \propto QH

and

QH \propto \sqrt{H}D^{2}

So,

P \propto H^{\frac{3}{2}} D^{2}

Therefore,

\frac{P_{s}}{P_{p}} = \frac{D_{s}^{2} H_{s}^{\frac{3}{2}}}{D_{p}^{2} H_{p}^{\frac{3}{2}}}

\frac{P_{s}}{P_{p}} = \frac{D_{s}^{2} H_{s}^{\frac{3}{2}}}{D_{p}^{2} H_{p}^{\frac{3}{2}}}

\frac{P_{s}}{P_{p}} = \frac{1^{2}\times 5^{\frac{3}{2}}}{4^{2}\times 1^{\frac{3}{2}}}

\frac{P_{s}}{P_{p}} = \frac{5\sqrt{5}}{16}

{P_{s}}:{P_{p}} = {5\sqrt{5}}:{16}

8 0
3 years ago
Define the Static Balancing.
liubo4ka [24]

Answer: Static Balancing is when a stationary object has the the ability to balance because its core centre of gravity is on the axis of rotation.

8 0
3 years ago
A sample of wastewater is diluted 10 times. The diluted solution has an ultimate biochemical oxygen demand (BOD), Lo, of 30 mg/L
zzz [600]

Answer:

474.59 mg/L

Explanation:

Given that

BOD = 30 mg/L

Original BOD  = 30 mg/L × dilution factor

Original BOD  = 30 mg/L  × 10 = 300 mg/L

L_o = \frac{BOD}{1-e^{-5t}}

here L_o is the ultimate BOD ; BOD is the  biochemical oxygen demand ;  t = 0.20 /day

L_o = \frac{300}{1-e^{-5(0.20)}}

L_o = 474.59 \ mg/L

3 0
4 years ago
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