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adoni [48]
2 years ago
14

If the value of the feedback resistor in the filter is changed but the value of the resistor in the forward path is unchanged, w

hat characteristic of the filter is changed?
Engineering
1 answer:
Sholpan [36]2 years ago
6 0

Answer:

The cut off frequency and the  passband gain will change

Explanation:

Answer :

Since the cut off frequency ω and the passband gain K are the function of the feedback of the resistor R2, Both K  and ω will change.

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3. How can statistical analysis of a dataset inform a design process?<br> PLEASE I NEED THIS ANSWER
julia-pushkina [17]

Answer:

you have to think then go scratch and then calculate and the design  

Explanation:

4 0
2 years ago
Vivian's Violins has sales of $326,000, contribution margin of $184,000 and fixed costs total $85,000. Vivian's Violins net oper
frosja888 [35]

Based on the calculations, Vivian's Violins net operating income is equal to: D. $99,000.

<h3>How to calculate net operating income?</h3>

Mathematically, the net operating income of an individual or business firm can be calculated by using this formula:

Net operating income = Contribution margin - Total fixed costs

<u>Given the following data:</u>

  • Sales = $326,000
  • Contribution margin = $184,000
  • Fixed costs total $85,000

Substituting the given parameters into the formula, we have;

Net operating income = $184,000 - $85,000

Net operating income = $99,000.

Read more on net operating income here: brainly.com/question/24165947

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5 0
1 year ago
Technician A says independent shops are not affiliated with vehicle manufacturers, but it is easy for technicians who work in th
KatRina [158]

Answer:

b

Explanation:

i did it yeater dayajsbs

8 0
3 years ago
weight of 1000 pounds is suspended from two cables. The allowable stress in the cables is 1500 psi. Find the minimum diameter fo
kari74 [83]

Answer:

The minimum diameter for each cable should be 0.65 inches.

Explanation:

Since, the load is supported by two ropes and the allowable stress in each rope is 1500 psi. Therefore,

(1/2)(Weight/Cross Sectional Area) = Allowable Stress

Here,

Weight = 1000 lb

Cross-sectional area = πr²

where, r = minimum radius for each cable

(1/2)(1000 lb/πr²) = 1500 psi

500 lb/1500π psi = r²

r = √1.061 in²

r = 0.325 in

Now, for diameter:

Diameter = 2(radius) = 2r

Diameter = 2(0.325 in)

<u>Diameter = 0.65 in</u>

7 0
2 years ago
A viscous fluid flows in a 0.10-m-diameter pipe such that its velocity measured 0.012 m away from the pipe wall is 0.8 m/s. If t
maksim [4K]

Answer:

A) centerline velocity = 1.894 m/s

B) flow rate = 7.44 x 10^(-3) m³/s

Explanation:

A) The flow velocity intensity for the input radial coordinate "r" is given by;

U(r) = (Δp•D²/16μL) [1 - (2r/D)²]

Velocity at the centre of the tube can be expressed as;

V_c = (Δp•D²/16μL)

Thus,

U(r) = (V_c)[1 - (2r/D)²]

From question, diameter = 0.1m,thus radius (r) = 0.1/2 = 0.05m

But we are to find the velocity at the centre of the tube, thus;

We will use the radius across the horizontal distance which will be;

0.05 - 0.012 = 0.038m

Thus, let's put 0.038 for r in the velocity intensity equation and put other relevant values to get the velocity at the centre.

Thus;

U(r) = (V_c)[1 - (2r/D)²]

0.8 = (V_c)[1 - {(2 * 0.038)/0.1}²]

0.8 = (V_c)[1 - (0.76)²]

V_c = 0.8/0.4224 = 1.894 m/s

B) flow rate is given by;

ΔV = Average Velocity x Area

Now, average velocity = V_c/2

Thus, average velocity = 1.894/2 = 0.947 m/s

Area(A) = πr² = π x 0.05² = 0.007854 m²

So, flow rate = 0.947 x 0.007854 = 7.44 x 10^(-3) m³/s

4 0
3 years ago
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