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Mashcka [7]
3 years ago
7

Which geometric shape can be described as a fixed distance along a line?

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
8 0
<span>A line segment is described as a fixed distance along a line. This is because a line segment has a definitive start point and an end point, and it falls along one line.</span>
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6 cell phones weigh 46.2 ounces. Fourteen cell phones weigh 107.8 ounces. Does this represent a proportional relationship
Studentka2010 [4]

yes, because 46.2/6 = 7.7 ounces and 107.8/14 = 7.7 ounces

3 0
3 years ago
Read 2 more answers
The Factors shot 5 rolls of film with 36 exposures on each roll. It cost $14.85 to process each roll. How much did it cost for e
kondor19780726 [428]
Your answer is .41, hope this helps
6 0
3 years ago
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In $\triangle abc$, points $x$ and $z$ are on $\overline{ab}$ and $y$ is on $\overline{ac}$ such that $\overline{xy}\parallel \o
svp [43]

To solve this problem, we must imagine the triangles and parallel lines which are formed. It is best to draw the triangle described in the problem so that you can clearly understand what I will be talking about.

The first step we have to do is to make an equality equation in triangle ABC.

In triangle ABC, we are given that lines XY and BC are two parallel lines (XY || BC).  Therefore this means that:

AX / XB = AY / YC                                              ---> 1

 

The next step is to make an equality equation in triangle AXC.

We are given that lines ZY and XC are two parallel lines (ZY || XC). Therefore this also means that:

AZ / ZX = AY / YC                                               ---> 2

 

Combining 1 and 2 since they have both AY / YC in common:

AX / XB = AZ / ZX

we are given that:

AZ = 8, ZX = 4 therefore AX = AZ + ZX = 12, hence

12 / XB = 8 / 4

XB = 6

7 0
3 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
3 years ago
Aanya lives in Ohio. She immigrated with her family from India to North America. Aanya wants to visit a cousin in Toronto by dri
Genrish500 [490]

Answer:

(b) 310 mi, 12.76km/liter

Step-by-step explanation:

We are told that Toronto is 500 km north on Highways. Since 1 km = 0.62 mi, then Toronto is: 500 × 0.62 = 310 miles

Aanya’s car averages 30 mi/gallon.

We are told that 1 mi = 1.61 km

Thus, her average is now;

30 × 1.61 km/gallon = 48.3 km/gallon

We are told that 1 qt = 0.946 liters

But also, 0.25 gallon = 1 qt

Thus;

0.25 gallon = 0.946 litres

Thus, 1 gallon = 0.946/0.25 litres = 3.784 litres

Thus, 48.3 km/gallon to km/litres = 48.3/3.784 = 12.76 km/litres

Answer is 310 miles and 12.76 km/litres

7 0
3 years ago
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