Which geometric shape can be described as a fixed distance along a line?

1 answer:

8 0

<span>A line segment is described as a fixed distance along a line. This is because a line segment has a definitive start point and an end point, and it falls along one line.</span>

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Talja [164]

21 sq inches bc it just is i think :))

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bagirrra123 [75]

The answer would be 9. Hope that helped!

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sineoko [7]

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Tems11 [23]

Answer:

$x + 5y = 6$ is perpendicular to $y = 5x + \frac{6}{5}$ and parallel to $y = -\frac{1}{5}x + 2\\$

Step-by-step explanation:

First, convert the equation to standard form so that y is isolated.

x + 5y = 6 --> x - 6 = -5y (divide both sides by -5) --> $y = -\frac{1}{5}x + \frac{6}{5}$

A perpendicular line will have a slope that is the opposite reciprocal of the original slope (meaning you flip the numerator and denominator then make it negative).

$-\frac{1}{5}$ is perpendicular to $-(\frac{-5}{1} )$ which simplifies to 5.

A parallel line will have the same slope, but the y-intercept will be different. It can be pretty much any number as long as the original slope is used in the new equation.

$y = -\frac{1}{5}x + \frac{6}{5}\\$ is parallel to $y = -\frac{1}{5}x + 2\\$ just like $y = -\frac{1}{5}x - \frac{100}{23}$ .

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Scilla [17]

The explanation is:

The definition of "secant of (x)" is: 1 / (sine of x) .

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