A regular octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in cm and the area is 392.4 in2. A second octago
n has side lengths equal to 21.8 in. Find the area of the second octagon. Round to the nearest hundredth.
2 answers:
Answer:
1569.6 in^2
Step-by-step explanation:
(392.4 in² / x in²) = (10.9 / 21.8)^2
The value of x from the equation is 1569.6 in^2
Hello,
c1=10.9 (in) A1=392.4 (in²)
c2=21.8 (cm) =21.8/2.54 (in)
k=c2/c1=(21.8/(2.54*10.9)=2/2.54
A2=(2/2.54)²*392.4=243,28848...≈243.29 (in²)
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