5H₂SO₄ + 8NaI = 4I₂ + 4H₂O + H₂S + 4Na₂SO₄
S⁺⁶ + 8e⁻ = S⁻² f=8
2I⁻ - 2e⁻ = I₂
M(H₂SO₄)=98 g/mol
M(eqi)=98/8=12.25 g/mol
Answer is: the molarity of HCl found in a titration is 0.1 M.
Balanced chemical reaction between hydrochloric acid and sodium hydroxide:
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l).
From balanced chemical reaction: n(HCl) : n(NaOH) = 1 : 1.
n(HCl) = n(NaOH).
c(HCl) · V(HCl) = c(NaOH) · V(NaOH).
c(HCl) = c(NaOH) · V(NaOH) ÷ V(HCl).
c(HCl) = 0.1 M · 50 ml ÷ 50 ml.
c(HCl) = 0.1 M; molarity of hydrochloric acid.
Answer:
They used atomic number instead of atomic mass to organize the elements. From an element's location in the periodic table, you can predict: ... The elements have similar properties.
Moles XeF6 = 10.0g/ 245.28 g/ mol=0.0408
The ratio between F2 and XeF6 is 3:1
Moles F2 required = 3 x 0.0408=0.122
Mass F2 = 0.122 mol x 37.9968 g/ mol=4.64g
Actual volume=Final Volume-initial volume
Now
