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arlik [135]
2 years ago
15

Evan watches the weather report on the news. The announcer states that an air mass formed over a tropical ocean is moving into t

he area where Evan lives. Which type of weather can Evan expect?
Chemistry
2 answers:
Nezavi [6.7K]2 years ago
5 0
Evan can expect windy and rainy weather
AlexFokin [52]2 years ago
4 0
This is a maritime air mass. Evan can expect warm and humid weather.
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Consider this equation: 2.524 g (5.1 × 106 g) ÷ (6.85 × 103 g) = ? How many significant figures should the result have?
weqwewe [10]

Answer:

7

Explanation:

2.524g(5.1)(106)g

(6.85)(103)g

=

1364.4744g2

705.55g

=

1364.4744g

705.55

=

1364.4744g

705.55

=1.933916g

6 0
3 years ago
4. Using your knowledge of elements, compounds
igor_vitrenko [27]

Answer:

Element

magnesium, hydrogen, chlorine, sulfur

Compound

water, iron oxide

Mixture

air, salty water , dias cola.

Explanation:

Element is made up of only one type of atom and are relresented by symbols.

Compound are formed by chemical mixing of atoms of elements and have a chemical formula

Mixture are formed by simple mixing up of substances and mixture don't have chemical formula.

4 0
2 years ago
Phosgene, a poisonous gas, when heated will decompose into carbon monoxide and chlorine in a reversible reaction: COCl2 (g) <
Advocard [28]

Answer:

8.08 × 10⁻⁴

Explanation:

Let's consider the following reaction.

COCl₂(g) ⇄ CO (g) + Cl₂(g)

The initial concentration of phosgene is:

M = 2.00 mol / 1.00 L = 2.00 M

We can find the final concentrations using an ICE chart.

     COCl₂(g) ⇄ CO (g) + Cl₂(g)

I       2.00            0            0

C        -x             +x           +x

E    2.00 -x          x             x

The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.

The concentrations at equilibrium are:

[COCl₂] = 2.00 -x = 1.96 M

[CO] = [Cl₂] = 0.0398 M

The equilibrium constant (Keq) is:

Keq = [CO].[Cl₂]/[COCl₂]

Keq = (0.0398)²/1.96

Keq = 8.08 × 10⁻⁴

4 0
3 years ago
An unknown metal has a mass of 86.8 g. When 5040 J of heat are added to the sample, the sample temperature changes by 64.7 ∘ C .
grandymaker [24]

Answer: The specific heat of the unknown metal is 0.897J/g^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=5040 Joules

m= mass of substance = 86.8 g

c = specific heat capacity = ?

Initial temperature of the water = T_i

Final temperature of the water = T_f

Change in temperature ,\Delta T=T_f-T_i=(64.7)^0C

Putting in the values, we get:

5040=86.8\times c\times 64.7^0C

c=0.897J/g^0C

The specific heat of the unknown metal is 0.897J/g^0C

4 0
3 years ago
NEED HELP NOW 62 POINTS WILL MARK BRAINLIEST!!! PLZ ANSWER ALL AND DO NOT COPY OFF WEBSITE QUESTIONS DOWN BELOW
Karolina [17]
#19 due to weathering and erosion the rock from the stream was smoothened and without as much the rock from deep underground was/is very rugged and natural.

#18 Due to wind patterns the sand dunes are blew around and the sands shift and fly around with nothing to keep the sand in place the sand can go long distances or come long distances.
4 0
2 years ago
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