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mojhsa [17]
3 years ago
10

Explain why human being is regarded as a complex machine.

Chemistry
2 answers:
Masteriza [31]3 years ago
7 0

Answer:

Well a human bein is a complex organism with pain and emotion.

There is a very very complex brain that recives and sends sis also faster than the eye can see.

Thats why when you touch a hot surface a lighting fast signal is sent from the hand to the brain and the brain sends a signal back to the hand to tell it what to do and this all happens a faster than a second.

A human is made out of millions, billions, trillions, and quadrillions if cells working together to perform special tasks like eating, walking, and talking.

tia_tia [17]3 years ago
3 0

Answer:

Humans are the only known species that are able to think as complexly as we do. For example, animals are not able to have <em>thoughts about their thoughts. </em>Animals are not able to ponder the existence of our universe, develop calculus, chemical solutions, etc. There are many other <em>intelligent species</em>- like chimpanzees and octopi. However, both of those species are limited in the type of communication, emotion, and complex thinking skills that they possess compared to human beings.

Explanation:

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Gennadij [26K]
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(Please help!)
Inessa [10]

Answer:

B. temperature decreases as altitude increases.

Explanation:

Just like in the lower reaches of the atmosphere, the troposphere, in the mesosphere, temperature decreases as altitude increases.

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4 years ago
Dinitrogen trisulfide symbol
notka56 [123]
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4 0
3 years ago
Read 2 more answers
Se hace reaccionar 4,00 g de aluminio y 42,00 g de bromo, según la reacción: Al(s)+Br2(l)⟶AlBr3(s) Calcular las moles de AlBr3(s
NeX [460]

Answer:

0.145 moles de AlBr3.

Explanation:

¡Hola!

En este caso, al considerar la reacción química dada:

Al(s)+Br2(l)⟶AlBr3(s)

Es claro que primero debemos balancearla como se muestra a continuación:

2Al(s)+3Br2(l)⟶2AlBr3(s)

Así, calculamos las moles del producto AlBr3 por medio de las masas de ambos reactivos, con el fin de decidir el resultado correcto:

n_{AlBr_3}^{por\ Al}=4.00gAl*\frac{1molAl}{27gAl} *\frac{2molAlBr_3}{2molAl}=0.145mol AlBr_3\\\\n_{AlBr_3}^{por\ Br_2}=42.00gr*\frac{1molr}{160g Br_2} *\frac{2molAlBr_3}{3molBr_2}=0.175mol AlBr_3

Así, inferimos que el valor correcto es 0.145 moles de AlBr3, dado que viene del reactivo límite que es el aluminio.

¡Saludos!

3 0
3 years ago
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