Answer:
0.015 M HNO3 = 0.015 M H3O+ pH = -log(0.015) = 1.82 [OH -] = 1.0 x 10 -14/0.015 M = 6.7 x 10 13 Check: HNO3 is a strong acid, so we expect the pH to be low and the [OH ] to be small
1.75 moles of Solute or 1.75n.
To find this, you'll need to use the molarity equation which is M = 
List the given items to organize better:
M (Molarity) = .35
V (Volume) = 5L [must always be in Liters]
n (Moles) = ?
Now, for the equation, substitute the variables with the given numbers:
.35 = 
Isolate the variable by multiplying the volume, 5, onto both sides. This will give you the answer of:
1.75 = n
Hope this helps!
Answer:
The answer to the question is letter a. 2
Explanation:
Write the formula of each compound
Calcium hydroxide = Ca(OH)₂
Nitric acid = HNO₃
Water = H₂O
Calcium nitrate = Ca(NO₃)₂
Chemical Reaction
Ca(OH)₂ + HNO₃ ⇒ Ca(NO₃)₂ + H₂O
Reactants Elements Products
1 Ca 1
1 N 2
3 H 2
5 O 7
Balanced Chemical Reaction
Ca(OH)₂ + 2HNO₃ ⇒ Ca(NO₃)₂ + 2H₂O
Reactants Elements Products
1 Ca 1
2 N 2
4 H 4
8 O 8