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TiliK225 [7]
3 years ago
9

Write the equation of the line that passes through the points (-2,6) and (4, 6). Put

Mathematics
1 answer:
ivolga24 [154]3 years ago
7 0

Answer:

y = 6

Step-by-step explanation:

Lets first try to find the slope between the two points. Note, if the slope is 0, then the line would be a horizontal line. If the slope is undefined, then it is a vertical line.

We can use the slope formula to find the slope between the two lines, but notice something. The slope formula is technically just the change in y divided by the change in x. Between the two points, the y-value does not change and the x-value does change. This means that the change in y is 0, but the change in x is not zero. This means that the slope would be 0, resulting in a horizontal line.

Now, we know that the resulting line is horizontal, meaning it will take the form of y = _. Since the y-values for both of the points is 6, it makes sense to say that the equation for the line would be y = 6.

I hope this helps. Happy studying.

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A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

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