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ivann1987 [24]
1 year ago
5

HI!! Please answer this!

Mathematics
1 answer:
bezimeni [28]1 year ago
8 0

Answer:

41 ≤ x

x ≤ 45

Step-by-step explanation:

You might be interested in
Approximately 5% of calculators coming out of the production lines have a defect. Fifty calculators are randomly selected from t
baherus [9]

Answer:

0.2611 = 26.11% probability that exactly 2 calculators are defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. The probability of a calculator being defective is independent of any other calculator, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of calculators coming out of the production lines have a defect.

This means that p = 0.05

Fifty calculators are randomly selected from the production line and tested for defects.

This means that n = 50

What is the probability that exactly 2 calculators are defective?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{50,2}.(0.05)^{2}.(0.95)^{48} = 0.2611

0.2611 = 26.11% probability that exactly 2 calculators are defective.

3 0
2 years ago
!000000000 to the 5th power?
Elena L [17]

Answer:

i will just give you the answer <u><em>1e+45</em></u>

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
Help i’ll give u a brainliest if u get it right
Goryan [66]

Answer:

A i think

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Exercice 2: Un remorqueur tire un bateau à la vitesse de 10 noeuds. La tension du câble est de 2500N, Le câble est parallèle à l
Elza [17]

Répondre:

1 285 watts

Explication étape par étape:

La puissance est exprimée selon la formule;

power = travail effectué / temps

Puissance = Force * (distance / temps)

Depuis Vitesse = distance / temps

Puissance = Force * vitesse

Donné

Force = 2500N

Vitesse (en m / s) = 0,514 m / s

Obligatoire

Puissance

Remplacez la formule donnée;

Puissance = 2500 * 0,514

Puissance = 1,285Watts

Par conséquent, la puissance correspondante requise est de 1285 watts

5 0
3 years ago
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