First factor out 2
2(x^4 - y^4)
Rewrite it as ((x^2)^2) and ((y^2)^2)
Then you get..
2 ((x^2)^2) - (y^2)^2))
Now both terms are perfect squares, factor using the difference of squares formula, a^2 + b^2 = (a+b)(a-b)
a= x^2 and b= y^2
2((x^2 + y^2)(x+y)(x-y))
clean it up!
2(x^2 + y^2)(x+y)(x-y)
A Pentagon has 5 sides, therefore just divide 100 into 5 sides .
100÷5 = 20 centimeters
So you want to make one of the equations equal to one of the placeholders exg y=x+3
so we have
x+y=2 and
-2x+y=2
I chose to make -2x+y=2 equal to y so
-2x+y=2
add 2x to both sides
y=2+2x
subsitute 2+2x for y in x+y=2
x+2+2x=2
add like terms
3x+2=2
subtract 2 from both sides
3x=0
x=0
subsitute x=0 in x+y=2
0+y=2
y=2
x=0
y=2
Answer:
4/6
since a dice has 6 sides and 1,2,3, and 4 are under 5
Step-by-step explanation:
