the amnwer is 1.6. all you do is 8 dived by 5
This is a systems of equations.
s = stamp, e = envelope

Substitute e + 9 for s.
.1(e + 9) + .13e = 2.51
Simplify.
.1e + .9 + .13e = 2.51
Simplify.
.14e + .9 = 2.51
Subtract .9 from both sides.
.14e = 1.61
Divide both sides by .14.
e = 11.5
Now, you can input e into the other equation.
11.5 + 9 = s
Simplify.
20.5 = s
s = 20.5, e = 11.5
Using a t-distribution calculator, it is found that the critical value of the test statistic t is
.
<h3>How to find the critical value of a t-test?</h3>
- The critical value is found using a calculator.
The inputs are:
- The amount of degrees of freedom, which is one less than the sample size.
In this problem, we have a<u> lower(left-tailed) test, with 10 - 1 = 9 df and a level of significance of 0.1</u>, hence the critical value is
.
You can learn more about the t-distribution at brainly.com/question/26062194
20*3/4 = 60/4....and 60/4 = 15