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umka21 [38]
4 years ago
5

What is 1,000×200help me pls

Mathematics
1 answer:
dybincka [34]4 years ago
4 0
1000*200=200000
This will be your answer
thanks
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Use the table to identify values of p and q that can be used to factor
liberstina [14]
It would be C. -2 and 6
3 0
3 years ago
John is skiing on a mountain with an altitude of 1200 feet. The angle of depression is 21 About how far does
Agata [3.3K]

Answer:

John ski down the mountain is 1285.37 feet.

Step-by-step explanation:

Given : John is skiing on a mountain with an altitude of 1200 feet. The angle of depression is 21.

To find : About how far does  John ski down the mountain ?

Solution :

We draw a rough image of the question for easier understanding.

Refer the attached figure below.

According to question,

Let AB be the height of mountain i.e. AB=1200 feet

The angle of depression is 21 i.e. \theta=21^\circ

We have to find how far does  John ski down the mountain i.e. AC = ?

Using trigonometric,

\cos\theta = \frac{AB}{AC}

\cos(21)= \frac{1200}{AC}

AC=\frac{1200}{\cos(21)}

AC=1285.37

Therefore, John ski down the mountain is 1285.37 feet.

7 0
4 years ago
A)<br> zero<br> B)<br> positive<br> negative<br> D)<br> undefined
marusya05 [52]

Answer:

I think it's positive

Step-by-step explanation:

6 0
3 years ago
Use the diagram below for #10.
Studentka2010 [4]

Answer:

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3 years ago
1. A gambler makes 100 column bets at roulette. The chance of winning on any one play is 12/38. The gambler can either win $ 5 o
lapo4ka [179]

Answer:

a) Expected amount of the gambler's win = $0.209

b) SD = 2.26

c)P (X >1) = P(z >0.35) = 0.36317

Step-by-step explanation:

The probability of winning, p = 12/38 =6/19

Probability of losing, q = 1 -p = 1-6/19

q = 13/19

Win amount = $5

Loss amount = $2

a) Expected total amount of win = ((6/19)*5) - ((13/19)*2)

Expected total amount of win = 1.579 - 1.369

Expected amount of win, E(X) = $0.209

b) Standard Deviation for the total amount of the gambler's win

SD = \sqrt{E(X^{2}) - (E(X))^{2} }

E(X²) = (6/19)*5²  -  (13/19)*2²

E(X²) = 5.158

SD = \sqrt{5.158 - 0.209^2}

SD = 2.26

c)  probability that, in total, the gambler wins at least $1.

P(X >1)

z = \frac{X - \mu}{\sigma}

μ = E(x) = 0.209

z = (1-0.209)/2.26

z = 0.35

P( X >1) = P(z >0.35)

P(z >0.35) = 1 - P(z <0.35)

P(z >0.35) = 1 - 0.63683

P(z >0.35) = 0.36317

5 0
4 years ago
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