Hello,
A(x)=x²-x-72 (m²)
L=(x+8) (cm)= (x+8)/100 (m)
We suppose here x≠-8
(in reality x²-x-72>0 ==>x<-8 or x>9
but x+8>0 ==> x>-8
then
only x>9 are solutions)
W=A(x)/ ((x+8)/100 )=100*(x²-x-72)/(x+8)= 100*(x-9)(x+8)/(x+8)=100*(x-9)
Answer:
Yes, Mina is correct
Step-by-step explanation:
Let the triangles be A and B
Given
Triangle A:

Triangle B:

Required
Is Mina's claim correct?
First, we calculate the third angle in both triangles.
For A:


For B:


For triangle A, the angles are: 34, 57 and 89
For triangle B, the angles are: 34, 57 and 89
<em>Since both triangles have the same angles, then by the postulate of AAA (Angle-Angle-Angle), the triangles are similar.</em>
For this case we have that by definition, the Pythagorean theorem states that:

Where:
a, b: Are the legs
c: It is the hypotenuse
According to the figure we have to:

Substituting in the formula we have:

Answer:
Option D
Answer:
Part 1) The area of the circle is 
Part 2) The circumference of the circle is 
Step-by-step explanation:
step 1
The area of a circle is equal to

we have
---> the radius is half the diameter

substitute


step 2
The circumference of a circle is equal to

we have

substitute


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