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MariettaO [177]
3 years ago
7

Simplify the expression: 3x2(x2 - 4x - 2) + (5x3 + 7x2 + 2x + 11) Show and explain your steps.

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0
Are they suppose to be squared ?

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the area of a rectangular field is x^2-x-72 m^2. The length of the field is x+8 cm. What is the width of the field meters.
Gre4nikov [31]
Hello,


A(x)=x²-x-72 (m²)
L=(x+8) (cm)= (x+8)/100 (m)

We suppose here x≠-8
(in reality x²-x-72>0 ==>x<-8 or x>9
but x+8>0 ==> x>-8
 then
only x>9 are solutions)

W=A(x)/ ((x+8)/100 )=100*(x²-x-72)/(x+8)= 100*(x-9)(x+8)/(x+8)=100*(x-9)

5 0
3 years ago
Mina says triangle A with angles
kotykmax [81]

Answer:

Yes, Mina is correct

Step-by-step explanation:

Let the triangles be A and B

Given

Triangle A:

Angles = 34, 57

Triangle B:

Angles = 89, 57

Required

Is Mina's claim correct?

First, we calculate the third angle in both triangles.

For A:

Third\ Angle = 180 - 34 - 57

Third\ Angle = 89

For B:

Third\ Angle = 180- 89 - 57

Third\ Angle = 34

For triangle A, the angles are: 34, 57 and 89

For triangle B, the angles are: 34, 57 and 89

<em>Since both triangles have the same angles, then by the postulate of AAA (Angle-Angle-Angle), the triangles are similar.</em>

3 0
3 years ago
The value of c is equal to _____.
DENIUS [597]

For this case we have that by definition, the Pythagorean theorem states that:

c = \sqrt {a ^ 2 + b ^ 2}

Where:

a, b: Are the legs

c: It is the hypotenuse

According to the figure we have to:

a = 20\\b = 21

Substituting in the formula we have:

c = \sqrt {(20) ^ 2 + (21) ^ 2}\\c = \sqrt {400 + 441}\\c = \sqrt {841}\\c = 29

Answer:

Option D

8 0
3 years ago
Find the area and the circumference of a circle with a diameter 8yrd.
nalin [4]

Answer:

Part 1) The area of the circle is A=50.24\ yd^2

Part 2) The circumference of the circle is C=25.12\ yd

Step-by-step explanation:

step 1

The area of a circle is equal to

A=\pi r^{2}

we have

r=8/2=4\ yd ---> the radius is half the diameter

\pi =3.14

substitute

A=(3.14)(4)^{2}

A=50.24\ yd^2

step 2

The circumference of a circle is equal to

C=\pi D

we have

D=8\ yd

\pi =3.14

substitute

C=(3.14)8

C=25.12\ yd

3 0
3 years ago
(3-2sqrt-18)-(2+3sqrt-8)​
Mama L [17]
Tell me the question and I’ll help you with it is it simplify or evalute etc.
7 0
3 years ago
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