Answer:
Check the explanation
Explanation:
An integer (int) is of two different bytes and each page has 200 bytes in length. What this means is that each row of array A (100 int) will fits perfectly in a page.
(a) For the initial or first array-initialization loop, one column is processed at a time, so a page fault will be generated at every inner loop iteration, with a total of 100*100=10,000 page faults.
(b) And when it comes to the second array-initialization loop, one row is processed at a time, and a page fault is generated at every outer loop iteration, with a total of 100 page faults.
Hence second array-initialization loop, has better spatial locality.
Answer:
because if you throttle it then
you can make sure it's okay
Answer:
The solution code is written in Python 3
- digits = input("Enter 9 digits: ")
-
- multiplier = 1
- total = 0
-
- for x in digits:
- total += int(x) * multiplier
- multiplier += 1
-
- checksum = total % 11
-
- if(checksum == 10):
- print(digits + "X")
- else:
- print(digits + str(checksum))
Explanation:
Firstly, use input function to get user input for 9 digits (Line 1)
Next we can use a for-loop to estimate the summation (d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5+ d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9) ( Line 6-8)
Then only apply % operator to get the remainder of total and get the checksum (Line 10)
Next create if and else statement to print the digits string joined with X if checksum is 10 else join digits string with checksum value (Line 12 -15)
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