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Sergio [31]
4 years ago
7

Which technology can allow a single ground-based telescope to achieve images as sharp as those from the Hubble Space Telescope?

Computers and Technology
1 answer:
Ganezh [65]4 years ago
7 0

Answer:

The correct answer to the following question will be "Adaptive Optics".

Explanation:

  • AO (Adaptive Optics) is a technique used to enhance optical system performance by reducing the impact of incoming gravitational wave distortions by compressing a mirror to compensate for the distortion.
  • It operates by calculating and compensating for defects in a wave-front with a system that corrects these errors as a deformable mirror or even a liquid crystal collection.
  • It is a technique that can make it possible for a single ground-based telescope to get images as clear as that of the Hubble Space Telescope.
  • Certain methods can achieve power resolution that exceeds the limit set by atmospheric distortion, for example, Aperture synthesis, Lucky imaging, and Speckle imaging.

Therefore, Adaptive Optics is the right answer.

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Ally made the net below to find the surface area of a box she was designing. The box measures 12 centimeters long by 9 centimete
jarptica [38.1K]

The area of the box is 972.

7 0
3 years ago
Programs for embedded devices are often written in assembly language. Some embedded processors have limited instructions, like M
oksano4ka [1.4K]

Answer:

#include <iostream>

using namespace std;

int main()

{

   char address[2];

   int tag, firstBit, secondBit, setNumber;

   int cache[4][2]={{1,5}, {2,4}, {3,2}, {6,0}};

   cout << "Enter the address as hex(in small letters: "<

   cin >> address;

   for (int i < 0; i < 8; i++){

       if (address[0] == '0'){

           tag = 0;

           firstBit = 0;

        } else if (address[0] == '1'){

           tag = 0;

           firstBit = 1;

        } else if (address[0] == '2'){

           tag =1;

           firstBit = 0;

        } else if (address[0] == '3'){

           tag = 1;

           firstBit = 1;

        } else if (address[0] == '4'){

           tag = 2;

           firstBit = 0;

        } else if (address[0] == '5'){

           tag = 2;

           firstBit = 1;

        }  else if (address[0] == '6'){

           tag = 3;

           firstBit = 0;

       } else if (address[0] == '7'){

           tag = 3;

           firstBit = 1;

       }  else if (address[0] == '8'){

           tag = 4;

           firstBit = 0;

       } else if (address[0] == '9'){

           tag = 4;

           firstBit = 1;

       }   else if (address[0] == 'A'){

           tag = 5;

           firstBit = 0;

       } else if (address[0] == 'B'){

           tag = 5;

           firstBit = 1;

       }  else if (address[0] == 'C'){

           tag = 6;

           firstBit = 0;

       } else if (address[0] == 'D'){

           tag = 6;

           firstBit = 1;

        }  else if (address[0] == 'E'){

           tag = 7;

           firstBit = 0;

       } else if (address[0] == 'F'){

           tag = 7;

           firstBit = 1;

       } else{

           cout<<"The Hex number is not valid"<< endl;

        }

   }

   if(address[1]>='0' && address[1]<'8'){

       secondBit = 0;

  }  else if(address[1]=='8'|| address[1]=='9'||(address[1]>='a' && address[1]<='f')){

       secondBit = 1;

   }  else{

       cout<<"The Hex number is not valid"<< endl;  

       return 0;

   }

   setNumber = firstBit * 2 + secondBit;

   if(cache[setNumber][0]==tag || cache[setNumber][1]==tag){

       cout<<"There is a hit";

   } else{

       cout<< "There is a miss";

   }

   return 0;

}

Explanation:

The C++ source code prompts the user for an input for the address variable, then the nested if statement is used to assign the value of the firstBit value given the value in the first index in the address character array. Another if statement is used to assign the value for the secondBit and then the setNumber is calculated.

If the setNumber is equal to the tag bit, Then the hit message is printed but a miss message is printed if not.

4 0
3 years ago
Consider the following import statement in Python, where statsmodels module is called in order to use the proportions_ztest meth
den301095 [7]

Answer:

a. count of observations that meet a condition (counts), total number of observations (nobs), Hypothesized value of population proportion (value).

Explanation:

In other to use the proportion_ztest method, the need to make import from the statsmodel module ; statsmodels.stats.proportion.proportions_ztest ; this will allow use use the Z test for proportion and once this method is called it will require the following arguments (count, nobs, value=None, alternative='two-sided', prop_var=False)

Where;

nobs = number of observations

count = number of successes in the nobs trial or the number of successes for each independent sample.

Value = hypothesized value of the population proportion.

7 0
3 years ago
When would it be necessary to edit the information shown on an electronic business card?
Goryan [66]

Answer:

Really depends on your situation. If you specified, I'd have an asnwer

3 0
3 years ago
Read 2 more answers
Anyone can help me with this?
dybincka [34]

Answer:

/*

 Find Largest and Smallest Number in an Array Example

 This Java Example shows how to find largest and smallest number in an  

 array.

*/

public class FindLargestSmallestNumber {

 

public static void main(String[] args) {

 

//array of 10 numbers

int numbers[] = new int[]{32,43,53,54,32,65,63,98,43,23};

 

//assign first element of an array to largest and smallest

int smallest = numbers[0];

int largetst = numbers[0];

 

for(int i=1; i< numbers.length; i++)

{

if(numbers[i] > largetst)

largetst = numbers[i];

else if (numbers[i] < smallest)

smallest = numbers[i];

 

}

 

System.out.println("Largest Number is : " + largetst);

System.out.println("Smallest Number is : " + smallest);

}

}

 

/*

Output of this program would be

Largest Number is : 98

Smallest Number is : 23

*/

Explanation:

5 0
2 years ago
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