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3 years ago

A=3 b=2 c=7a+b+c=??Help me please thank you

Mathematics

2 answers:

Natalija [7]3 years ago

8 0

Answer:

Step-by-step explanation:

Replace the letters by the given numbers

a+b+c

3+2+7

=12

tester [92]3 years ago

3 0

Answer: 13

Step-by-step explanation:

Given:

a+b+c, where a=3, b=2, c=7

Solve:

Given

a+b+c

Substitute values into the expression

=(3)+(2)+(7)

Combine like terms

=6+7

=13

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Help, please

Andreas93 [3]

Answer:

Step-by-step explanation:

7 0

3 years ago

four fifths of senior class went to prom. if 324 seniors went to prom, how many are there in the senior class

konstantin123 [22]

Answer:

The answer to your question is 405, because look divide 324 by 4 becasue thats how many fifths are being used then multiply the answer which is 81 by 405

Step-by-step explanation:

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3 years ago

Read 2 more answers

In Circle P, m EA=58, m BC=42, m CD=90, find:

elena55 [62]

Circle theorem states that the angle that an arc subtends at the center of a

circle is twice the angle subtended at the circumference.

The values are as follows;

m∠EDA = 90°
m∠BDC = 21°
m∠BEC = 21°
$m\widehat{AB}$ = 80°
m∠AEB = 40°
m∠ECA = 29°
m∠BAC = 21°
$m\widehat{ED}$ = 90°
m∠ECD = 45°
m∠ACB = 40°
m∠EBD = 45°
m∠ADB = 40°
m∠CAD = 45°
m∠EAB = 90°
m∠EBC = 90°

Reasons:

$\displaystyle 1. \ \mathbf{m\angle EDA} = \frac{1}{2} \cdot m\angle EPC$ Angle subtended at center is twice angle at circumference.

m∠EPC = 180°

∴ m∠EDA = 0.5 × 180° = 90°

2. $m\widehat{BC}$ = 42°, therefore, m∠BPC = 42°

$\displaystyle \ m\angle BDC= \frac{1}{2} \cdot m\angle BPC$

m∠BDC = 0.5 × 42° = 21°

3. m∠BEC = m∠BDC = 21°

4. $m\widehat{AB}$ = 180° - (58° + 42°) = 80°

5. $\mathbf{m\widehat{AB}}$ = m∠APB by definition

m∠AEB = 0.5 × m∠APB

m∠AEB = 0.5 × 80° = 40°

6. m∠ECA = 0.5 × m∠AE

Therefore;

m∠ECA = 0.5 × $m\widehat{EA}$

m∠ECA = 0.5 × 58° = 29°

m∠ECA = 29°

7. m∠BAC = 0.5 × $\mathbf{m\widehat{BC}}$

m∠BAC = 0.5 × 42° = 21°

m∠BAC = 21°

8. $m\widehat{ED}$ = 180° - $\mathbf{m\widehat{CD}}$

$m\widehat{ED}$ = 180° - 90° = 90°

$\mathbf{m\widehat{ED}}$ = 90°

9. m∠ECD = 0.5 × $\mathbf{m\widehat{ED}}$

m∠ECD = 0.5 × 90° = 45°

10. m∠ACB = 0.5 × $m\widehat{AB}$

m∠ACB = 0.5 × 80° = 40°

11. m∠EBD = 0.5 × $\mathbf{m\widehat{ED}}$

m∠EBD = 0.5 × 90° = 45°

12. m∠ADB = 0.5 × $\mathbf{m\widehat{AB}}$

m∠ADB = 0.5 × 80° = 40°

13. m∠CAD = 0.5 × $\mathbf{m\widehat{CD}}$

m∠CAD = 0.5 × 90° = 45°

14. m∠EAB = 0.5 × $\mathbf{m\widehat{EABC}}$

m∠EAB = 0.5 × 180° = 90°

15. m∠EBC = 0.5 × $\mathbf{m\widehat{EABC}}$

m∠EBC = 0.5 × 180° = 90°

Learn more about circle theorems here:

brainly.com/question/25101481

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3 years ago

Which of these strategies would eliminate a variable in the system of equations?

posledela

9514 1404 393

Answer:

A Subtract the bottom equation from the top equation.
B Add the equations.

Step-by-step explanation:

The x-terms are the same in each equation, so subtracting one equation from the other will eliminate the x-variable.

The y-terms are opposites in the two equations, so adding the two equations will eliminate the y-variable.

Both strategies (subtracting, adding) are applicable to this system of equations.

4 0

3 years ago

Solve: y= 7/3x-3 and y=11

Travka [436]

Answer:

x = 6

Step-by-step explanation:

Given

y = $\frac{7}{3}$ x - 3 and y = 11, thus

$\frac{7}{3}$ x - 3 = 11 ( add 3 to both sides )

$\frac{7}{3}$ x = 14

Multiply both sides by 3 to clear the fraction

7x = 42 ( divide both sides by 7 )

x = 6

3 0

3 years ago

Read 2 more answers

A=3 b=2 c=7a+b+c=??Help me please thank you​

A=3 b=2 c=7a+b+c=??Help me please thank you