In terms of computer networking. what is PING?

how is a two-dimensional array different from a traditional one dimensional array? From an ArrayList?

mrs_skeptik [129]

An ArrayList is just like a 1D Array except it's length is unbounded and you can add as many elements as you need. The only difference when making a 2D array is that you now have two sets of brackets, the first one representing the number of rows you want and the second representing your columns.

6 0

3 years ago

Write Java code that creates an array of n integers myArray, by taking n integers from the user with duplications, and do the fo

skad [1K]

Answer:

this should be what you need

Explanation:

import java.util.*;

public class ABC{

public static void main(String[] args) {

int n;

//create scanner object

Scanner sc = new Scanner(System.in);

//ask for size of array

System.out.print("Enter the size of array (n): ");

//read the input

n = sc.nextInt();

//create an array of n length

int [] myArray = new int[n];

//ask user for array elements

System.out.printf("Enter %d integers: ", n);

//read array elements

for(int i =0 ;i <5; i++)

myArray[i] = sc.nextInt();

//print the elements if myArray

System.out.print("1 - The values of myArray are: [");

for(int i =0 ; i < n; i++){

System.out.print(myArray[i]);

if(i < n-1)

System.out.print(", ");

}

System.out.print("]\n");

//calculate mean and sum of myArray elements

int sum = 0;

double mean = 0;

for(int i = 0; i < n; i++)

sum += myArray[i];

mean = (sum*1.0)/n;

//print the sum and mean of myArray

System.out.printf("2 - The sum is: %d. The mean is: %.1f\n", sum, mean);

//create an arraylist

ArrayList<Integer> myArrayList = new ArrayList<Integer>();

//copy the value of myArray to an arraylist without duplicates

for(int i = 0; i < n; i++){

if(!myArrayList.contains(myArray[i]))

myArrayList.add(myArray[i]);

}

sum = 0; mean = 0;

//display the values of myArrayList

System.out.print("3 - The values of myArrayList are: [");

for(int i =0 ; i < myArrayList.size(); i++){

System.out.print(myArrayList.get(i));

if(i < myArrayList.size()-1)

System.out.print(", ");

}

System.out.print("]\n");

//calculate sum and mean of myArrayList elements

for(int i = 0; i < myArrayList.size(); i++)

sum += myArrayList.get(i);

mean = (sum*1.0)/myArrayList.size();

//print the sum and mean of myArrayList

System.out.printf("4 - The sum is: %d. The mean is: %.2f\n", sum, mean);

}

3 0

3 years ago

A company set up controls to allow only a specific set of software and tools to install on workstations. A user navigates to a s

Jlenok [28]

Answer:

Whitelisting

Explanation:

What is Whitelisting

Application whitelisting specifies a list of application that are allowed to run, but no others are.

4 0

3 years ago

Write a program that takes as input a number of kilometers and prints the corresponding number of nautical miles. Use the follow

Dmitrij [34]

<h2>Answer:</h2>

import java.util.Scanner;

public class NauticalMiles{

public static void main (String [ ] args){

Scanner input = new Scanner(System.in);

System.out.println("Please enter the number of kilometers");

double km = input.nextDouble();

double nm = 0.54 * km;

System.out.println("The corresponding number of nautical miles is " + nm);

}

<h2>Explanation:</h2><h2></h2>

<em>1 => Pre-code analysis</em>

According to the question,

(a) <em>A nautical mile (nm) is 1 minute of an arc.</em>

=> 1 nm = 1 minute of an arc

(b)<em>There are 90 degrees, each containing 60 minutes of arc, between the North pole and the equator.</em>

=> Each of the degrees in 90 degrees has 60 minutes of arc

=> $1^{0}$ = 60 minutes of arc

=> $90^{0}$ = 90 x 60 minutes of arc

=> $90^{0}$ = 5400 minutes of arc

(c) <em>A kilometer (km) represents 1/10,000 of the distance between the North pole and the equator. </em>

=> A kilometer = (1 / 10000) x distance between the North pole and equator.

Remember that the distance between the North pole and the equator as shown in (b) above is 90 degrees which is equal to 5400 minutes of arc.

=> 1 km = (1 / 10000) x 5400 minutes of arc

=> 1 km = (1 / 10000) x 5400 x 1 minute of arc

As shown in (a) above, 1 minute of arc is 1 nautical mile(nm).

=> 1 km = (1 / 10000) x 5400 x 1 nm

=========================================================

<em>2 => The code analysis</em>

The code has been written in Java.

The following is the line-by-line explanation of the code written as comments.

// Import the scanner class to allow for user's inputs

import java.util.Scanner;

// Declare the main class to hold and run the application

public class NauticalMiles {

// Write the main method where execution will begin

public static void main (String [ ] args) {

// Create an object <em>input </em>of the Scanner class

Scanner input = new Scanner(System.in);

// Prompt the user to enter the number of kilometers

System.out.println("Please enter the number of kilometers");

// Store the user's input in a double variable called <em>km</em>

double km = input.nextDouble();

// Convert the input to nautical miles using the formula from the

// pre-code analysis above. i.e 1km = 0.54nm.

// Store the result in a double variable called <em>nm</em>

double nm = 0.54 * km;

// Print out the result (the nautical mile)

System.out.println("The corresponding number of nautical miles is " + nm);

} // End of main method

} // End of class declaration

=========================================================

<em>3 => Sample output</em>

> Please enter the number of kilometers

>> <em>45</em>

> The corresponding number of nautical miles is 24.3

8 0

4 years ago

17. When looking for information on a web site, what is the easiest method to find that information? The search button The searc

Ket [755]

Answer:

<h3>Using search engines</h3>

Explanation:

<h3>With billions of websites online today, there is a lot of information on the Internet. Search engines make this information easier to find. Let's look at the basics of using a search engine, as well as some techniques you can use to get better search results.</h3>

5 0

3 years ago