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Nastasia [14]
3 years ago
8

Write Java code that creates an array of n integers myArray, by taking n integers from the user with duplications, and do the fo

llowing:
1- Print the elements of myArray,
2- Calculate the sum and the mean of myArray elements,
3- Copy the values of myArray to an array list named myArrayList, the array list must contain the elements of myArray without duplication,
4- Calculate the sum and the mean of myArrayList elem
Computers and Technology
1 answer:
skad [1K]3 years ago
3 0

Answer:

this should be what you need

Explanation:

import java.util.*;

public class ABC{

 public static void main(String[] args) {

   int n;

   //create scanner object

   Scanner sc = new Scanner(System.in);

   //ask for size of array

   System.out.print("Enter the size of array (n): ");

   //read the input

   n = sc.nextInt();

   //create an array of n length

   int [] myArray = new int[n];

   //ask user for array elements

   System.out.printf("Enter %d integers: ", n);

   //read array elements

   for(int i =0 ;i <5; i++)

     myArray[i] = sc.nextInt();

   

   //print the elements if myArray

   System.out.print("1 - The values of myArray are: [");

   for(int i =0 ; i < n; i++){

     System.out.print(myArray[i]);

     if(i < n-1)

       System.out.print(", ");

   }

   System.out.print("]\n");

   //calculate mean and sum of myArray elements

   int sum = 0;

   double mean = 0;

   for(int i = 0; i < n; i++)

     sum += myArray[i];

   

   mean = (sum*1.0)/n;

   //print the sum and mean of myArray

   System.out.printf("2 - The sum is: %d. The mean is: %.1f\n", sum, mean);

     

   //create an arraylist

   ArrayList<Integer> myArrayList = new ArrayList<Integer>();

   //copy the value of myArray to an arraylist without duplicates

   for(int i = 0; i < n; i++){

     if(!myArrayList.contains(myArray[i]))

       myArrayList.add(myArray[i]);

   }

   sum = 0; mean = 0;

   //display the values of myArrayList

   System.out.print("3 - The values of myArrayList are: [");

   for(int i =0 ; i < myArrayList.size(); i++){

     System.out.print(myArrayList.get(i));

     if(i < myArrayList.size()-1)

       System.out.print(", ");

   }

   System.out.print("]\n");

   //calculate sum and mean of myArrayList elements

   for(int i = 0; i < myArrayList.size(); i++)

     sum += myArrayList.get(i);

   mean = (sum*1.0)/myArrayList.size();

   //print the sum and mean of myArrayList

   System.out.printf("4 - The sum is: %d. The mean is: %.2f\n", sum, mean);

 }

}

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A continuous and differentiable function f(x) with the following properties: f(x) is decreasing at x=−5 f(x) has a local minimum
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The continuous and differentiable function where f(x) is decreasing at x = −5 f(x) has a local minimum at x = −2 f(x) has a local maximum at x = 2 is given as: y = 9x - (1/3)x³ + 3.

<h3>What is a continuous and differentiable function?</h3>

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Given the parameters, we state that

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The local minimum is given as:
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the local maximum is given as

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Hence,

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To get y' we must multiply both equations to get:

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Collect like terms to derive:

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When y' is integrated, the result is

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F (-5) < 0

This means that:

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Collecting like terms we have:
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c < 3.33


Substituting C into

f(x) = 9x - x³/3 + c; we have

f(x) = 9x - x³/3 + 3, which is the same as  y = 9x - (1/3)x³ + 3.

Learn more about differentiable functions at:
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