Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
Answer:
Step-by-step explanation:
x² - x -6 = x² + 2x - 3x - 3*2
=x(x + 2) - 3(x + 2)
= (x + 2 )(x - 3)


There are 2,000 fifties in one hundred thousand
Y=k/x
2.5=k/6
k=15
wheny x=4, y=15/4
y=3.75
For this case we have the following expression:

For this case what you should do is observe the terms that are repeated in the given expression.
We have then:

It is the term that is present in the whole expression.
Therefore, by doing common factor we have:
Answer:
the GCF is:
option A: a 3 is missing at the beginning of the option.