Question 9
Given the segment XY with the endpoints X and Y
Given that the ray NM is the segment bisector XY
so
NM divides the segment XY into two equal parts
XM = MY
given
XM = 3x+1
MY = 8x-24
so substituting XM = 3x+1 and MY = 8x-24 in the equation
XM = MY
3x+1 = 8x-24
8x-3x = 1+24
5x = 25
divide both sides by 5
5x/5 = 25/5
x = 5
so the value of x = 5
As the length of the segment XY is:
Length of segment XY = XM + MY
= 3x+1 + 8x-24
= 11x - 23
substituting x = 5
= 11(5) - 23
= 55 - 23
= 32
Therefore,
The length of the segment = 32 units
Question 10)
Given the segment XY with the endpoints X and Y
Given that the line n is the segment bisector XY
so
The line divides the segment XY into two equal parts at M
XM = MY
given
XM = 5x+8
MY = 9x+12
so substituting XM = 5x+8 and MY = 9x+12 in the equation
XM = MY
5x+8 = 9x+12
9x-5x = 8-12
4x = -4
divide both sides by 4
4x/4 = -4/4
x = -1
so the value of x = -1
As the length of the segment XY is:
Length of segment XY = XM + MY
= 5x+8 + 9x+12
= 14x + 20
substituting x = 1
= 14(-1) + 20
= -14+20
= 6
Therefore,
The length of the segment XY = 6 units
X + 2y = -4
-x -x
2y = -x - 4
Divide all by 2
y = -x/2 - 2
y = (-1/2)x - 2
Answer: s > 5
Step-by-step explanation:
-s² + 25s - 100 > 0
Coefficient of s² is -1, multiply the equation through by -1.
-1 × (-s² + 25s - 100)
s² — 25s + 100
ax² + bx + c
Then you get the factors x and y that gives x + y = b and xy = c
b = -25 and c = 100, x = -20 and y = -5
-20 × -5 = 100 and -20 + -5 = -25
Then
s² — 20s — 5s + 100 > 0
Factorising,
s (s — 20) — 5(s — 20) > 0
(s — 5)(s — 20) > 0
(s — 5) > 0 and (s — 20) > 0
s>5 and s>20
s > 5
Hope this Helps?
Answer:
Step-by-step explanation:
You have to group all of the same one's together and however many there is, you add that number as the exponent.
There were 2 "(-2)" so that became 
, and there were 5 "7" so that became 
. You keep the symbol and put it together which became
