The mode is whichever one has the most so the mode would be 7. And the range is the highest number to the lowest. So 9-4 which is 5
Answer:
((2 x + 1) (4 x^2 - 2 x + 1))/8
Step-by-step explanation:
Factor the following:
x^3 + 1/8
Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:
(8 x^3)/8 + 1/8
(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:
(8 x^3 + 1)/8
8 x^3 + 1 = (2 x)^3 + 1^3:
((2 x)^3 + 1^3)/8
Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):
((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8
1^2 = 1:
((2 x + 1) ((2 x)^2 - 2 x + 1))/8
Multiply each exponent in 2 x by 2:
((2 x + 1) (2^2 x^2 - 2 x + 1))/8
2^2 = 4:
Answer: ((2 x + 1) (4 x^2 - 2 x + 1))/8
Answer:
(3,1) because x is 3 and y is 1.
Step-by-step explanation:
x+2y=5
3x+5y=14
Multiply first equation by 3:
3x+6y=15
3x+5y=14
Subtract 3x:
1y=1
Therefore, y = 1
Plug it back into 1st equation:
x+2(1)=5
x+2=5
Therefore, x = 3
Judging from your answers, it looks like (3,1) because x is 3 and y is 1.
I hope this helped!
