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yuradex [85]
4 years ago
6

Need help answers please

Mathematics
1 answer:
Alborosie4 years ago
5 0
No the first one worked not the second one
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Which is not a factor of 48? A. 8 B. 14 C. 16 D. 24
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14 is not a factor of 48
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Rewrite the following equation in exponential form log3 3=1
yawa3891 [41]

Answer: (X) = y => b^y = x

use that equation to get the exponential form

Step-by-step explanation:

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Find thee consecutive even integers such that the sum of twice the smallest number and three times the largest is 42
tekilochka [14]

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7,8,9

Step-by-step explanation:

The closest you can get to 42 with that equation and it has to use consecutive intergers is 41 and these numbers get you there.

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3 years ago
Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a
dolphi86 [110]

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

3 0
3 years ago
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