The kids have to wait for 1 hour to get their bags.
<u>Step-by-step explanation:</u>
Given that,
A bus with kids and a truck with their bags started moving from the school to the camp at the same time.
- The speed of the bus was 60 mph.
- It took kids 3 hours to reach the camp.
<u>To find the distance traveled by the bus :</u>
⇒ Distance = Speed × Time
⇒ 60 × 3
⇒ 180 m
∴ The distance is 180 m.
<u>To find the time taken by the truck to reach the camp :</u>
- The speed of the truck was 45 mph.
- We found the distance as 180 m.
Time taken = distance / speed.
⇒ 180 / 45
⇒ 4 hours.
∴ The time taken by the truck to reach the camp is 4 hours.
<u>To find how long the kids have to wait for their bags :</u>
The time taken by the truck to reach the camp - the time it took for the kids to arrive.
⇒ 4 hours - 3 hours
⇒ 1 hour.
∴ The kids have to wait for 1 hour to get their bags.
Answer:
36a2 - b2
Step-by-step explanation:
( 6a + b)( 6a - b)
36a2 - b2
6^2 a2 - b^2
x2 y2 = (xy)2
(6a)2 - b^2
(6a + b)(6a - b)
Hope that helps :)
(5-5) x
It is different because when you distribute the x it will make it 5x-5x while all the other equations are 5-5x
Answer:
Roger can earn $510 at most.
Step-by-step explanation:
We are given the function

Which gives the earnings of Roger when he sells v videos. Since the play’s audience consists of 230 people and each one buys no more than one video, v can take values from 0 to 230, i.e.

That is the practical domain of E(v)
If Roger is in bad luck and nobody is willing to purchase a video, v=0
If Roger is in a perfectly lucky night and every person from the audience wants to purchase a video, then v=230. It's the practical upper limit since each person can only purchase 1 video
In the above-mentioned case, where v=230, then

Roger can earn $510 at most.
Answer:
1.282, -0.5244,...
Step-by-step explanation:
We know that Z is a standard normal variate with mean =0, and std dev =1
a) z-score separates the highest 10% from the rest of the scores
= 90th percentile = 1.282
b) z-score separates the lowest 30% from the rest of the scores
= 30th percentile = -0.5244
c) z-score separates the lowest 40% from the rest of the scores
= 40th percentile = -0.2533
d) z-score separates the lowest 20% from the rest of the score
=20th percentile = -0.8416
