Trisha runs 3 miles every 50 minutes. At this rate, how many minutes did Trisha run in 12 miles?

Mathematics

1 answer:

SVEN [57.7K]3 years ago

5 0

Answer:

200 minutes ; 3 hours and 20 minutes.

Step-by-step explanation:

If you write a proportion in the form

miles/minutes = miles/minutes

you would get 3/50 = 12/x

from there you cross multiply to get

3x=600, and solve that to get 200 minutes.

another way was to see that 12 is 3*4, and multiply 50 by 4 to get the same answer.

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A piece of carpet is 8 feet wide and 12 feet long the carpet needs to be reduced by a scale farctor so that the reduced carpet i

Murljashka [212]

Answer: 6 ft ^ 2

Step-by-step explanation:

We have been given that a piece of carpet is 8 feet wide and 12 feet long. The carpet needs to be reduced by a scale factor so that the reduced carpet is 2 feet wide.

First of all, let us find the scale factor by which the width of the carpet has been reduced.

Original width of carpet x scale factor = 12

Dividing both sides by 8 feet we will get:

8 feet x Scale factor/8 ft = 2/8 ft

Scale Factor = 1/4

Let us find the length of carpet after reduced by a scale factor of 1/4.

Length of the carpet after reducing a factor of 1/4=12 ft x 1/4

Length of the carpet after reducing a factor of 1/4=3 ft.

Now we will multiply the reduced length and width of the carpet to find the area of reduced carpet.

Area of reduced carpet = 2 ft x 3 ft

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3 years ago

Eight rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other ro

Brums [2.3K]

Answer:

9.11*10^-4 %

Step-by-step explanation:

To find the probability, you simply need to find the possible outcomes that allows no rooks to be in danger, and the possible amount of ways to place the rooks.

For the first outcome, you start by putting 1 rook in the first columns, you have 8 possible rows to do this. The next rook in the next column will only have 7 possible rows, as you have to exclude the one where the previous rook is located. The next rook, 6 possibilities, the next 5, and so on. So we conclude that the total amount of ways so that none of the rooks can capture any of the other rooks is 8*7*6*5*4*3*2*1 = 8! = 40320

In order to find the total amount of ways to place the rooks, you can just use a combinatoric:

$\left[\begin{array}{ccc}64\\8\end{array}\right]= \frac{64!}{8!(64-8)!} = 4.43*10^9$