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3 years ago

Trisha runs 3 miles every 50 minutes. At this rate, how many minutes did Trisha run in 12 miles?

Mathematics

1 answer:

SVEN [57.7K]3 years ago

5 0

Answer:

200 minutes ; 3 hours and 20 minutes.

Step-by-step explanation:

If you write a proportion in the form

miles/minutes = miles/minutes

you would get 3/50 = 12/x

from there you cross multiply to get

3x=600, and solve that to get 200 minutes.

another way was to see that 12 is 3*4, and multiply 50 by 4 to get the same answer.

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The equation p=1.5r graphed find price p, in dollars for r pounds of rice

disa [49]

Answer:

Hope that help you mark me brinilylist

Step-by-step explanation:

Given that 5 pounds of rice at a store cost $6.50.

Then 1 pound of rice at a store cost = $6.50/5= $1.3

So the equation for the cost can be written as:

C=1.3P just like we write equation y=mx

Now we have to graph the cost C, vs pounds of rice.

Variable for Pounds of rice is not given so let it be "P"

So let's make a table for the number of pounds (P) and cost (C) we can graph the points from that table to get the final graph.

The Attached graph is the final graph.

3 0

3 years ago

Isabella spent less than $14.00 for glass beads ,paintbrushes ,poster board,and paint she spends $1.68 on beads and $3.96 on pai

Eduardwww [97]

Your answer is 19.53$ if you do add.

7 0

3 years ago

While at the music store Drew bought five CDs all at the same price. The tax on his purchase was six dollars and the total was $

Natalka [10]

Answer:

Step-by-step explanation:

61- 6= 55 55÷5= 11 dollara for each cd

8 0

3 years ago

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

Dmitriy789 [7]

Answer:

The median weight for shelter A is greater than that for shelter B.

The data for shelter B are a symmetric data set.

The interquartile range of shelter A is greater than the interquartile range of shelter B.

Step-by-step explanation:

The median weight for shelter A is greater than that for shelter B.

The median of A = 21 and the median of B = 18 true

The median weight for shelter B is greater than that for shelter A.

The median of A = 21 and the median of B = 18 false

The data for shelter A are a symmetric data set.

False, looking at the box it is not symmetric

The data for shelter B are a symmetric data set.

true, looking at the box it is symmetric

The interquartile range of shelter A is greater than the interquartile range of shelter B.

IQR = 28 - 17 = 11 for A

IQR for B = 20 -16 = 4 True

7 0

3 years ago

Read 2 more answers

Solve the equation <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%2B3%7D%2B4%3D5" id="TexFormula1" title=" \sqrt{x+3}+4=5" alt

Rama09 [41]

$D:x\geq-3\\\\
\sqrt{x+3}+4=5\\
\sqrt{x+3}=1\\
x+3=1\\
x=-2$

6 0

3 years ago