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3 years ago

Trisha runs 3 miles every 50 minutes. At this rate, how many minutes did Trisha run in 12 miles?

Mathematics

1 answer:

SVEN [57.7K]3 years ago

5 0

Answer:

200 minutes ; 3 hours and 20 minutes.

Step-by-step explanation:

If you write a proportion in the form

miles/minutes = miles/minutes

you would get 3/50 = 12/x

from there you cross multiply to get

3x=600, and solve that to get 200 minutes.

another way was to see that 12 is 3*4, and multiply 50 by 4 to get the same answer.

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select yes or no to indicate if a rectangle with the given dimensions whould have a perimeter of 50 inches

umka21 [38]

1a) no it would be 54

1b) yes

1c) yes

1d) no it would be 40

1e) yes

hope this helped

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3 years ago

Anyone know how to do the elimination method? pls help asap

givi [52]

Hey there!

Check out image!

Answer is (-7,5)

6 0

2 years ago

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During batting practice, Lenora hit 60% of the 20 pitches that were thrown to her. What fraction of the pitches thrown did Lenor

expeople1 [14]

Answer:

A 3/5

Step-by-step explanation:Here’s one way to solve this problem.

Write sixty percent as a fraction having a denominator of one hundred.

Now, change sixty-hundredths to an equivalent fraction having a denominator of twenty, the total number of pitches.

Do this by dividing the numerator and the denominator by five.

Then, simplify the fraction twelve-twentieths by dividing the numerator and the denominator by four.

So, Lenora hit three-fifths of the pitches.

6 0

3 years ago

Use a matrix to solve the system:

Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

$2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\$

Rewrite these equations in matrix form

$\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\$

we can write it like this,

$AX=B\\X=A^{-1}B$

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

$A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right] \\$

now multiply the matrix with B

$X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\$

4 0

3 years ago

Please Help!

Nadya [2.5K]

The answer is to ur question is b

4 0

4 years ago

Read 2 more answers