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valina [46]
3 years ago
10

Find the solution of this system of equations shown on the graph.

Mathematics
1 answer:
elena-s [515]3 years ago
3 0
Answer is (0,3)

hope it helps
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A scale factor of 3 was used, because Figure B's measurements are 3 times Figure A's measurements.
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1.75 as a improper fraction and mixed number in simplest form
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A 1.5-mm layer of paint is applied to one side of the following surface. Find the approximate volume of paint needed. Assume tha
Mariulka [41]

Answer:

V = 63π / 200  m^3

Step-by-step explanation:

Given:

- The function y = f(x) is revolved around the x-axis over the interval [1,6] to form a spherical surface:

                                 y = √(42*x - x^2)

- The surface is coated with paint with uniform layer thickness t = 1.5 mm

Find:

The volume of paint needed

Solution:

- Let f be a non-negative function with a continuous first derivative on the interval [1,6]. The Area of surface generated when y = f(x) is revolved around x-axis over the interval [1,6] is:

                           S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx

- The derivative of the function f'(x) is as follows:

                            f'(x) = \frac{21-x}{\sqrt{42x-x^2} }

- The square of derivative of f(x) is:

                            f'(x)^2 = \frac{(21-x)^2}{42x-x^2 }

- Now use the surface area formula:

                           S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi

- The Volume of the pain coating is:

                           V = S*t

                           V = 210*π*3/2000

                          V = 63π / 200 m^3

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3 years ago
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An absentminded professor does not remember which of his 12 keys will open his ocedoor. Suppose he tries them at random and with
kipiarov [429]

Answer: 0.0052

Step-by-step explanation:

Total number of times experiment was performed (n)= 12

Probability of the event (that one key out of a total of 12 opens the door) = 1/12 = 0.083

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x = 3

Since the experiment was performed n number of times, a binomial probability distribution can defined the experiment.

P(x=r) = nCr ×p^r × q^n-r

P(x=3) = 12C3 × (0.083)⁴ × (0.917)^8

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Which numbers are a distance of 5 units from 8 on a number line?
AysviL [449]

Answer:  3 and 13

Step-by-step explanation:

Observe the number line attached.

In order to find which numbers are a distance of 5\ units  from  8 on a number line, you can follow these steps:

First step: You must locate the number  8 on the number line.

Second step: Move 5\ units to the left. Notice that the distance between the numbers  3 and  8 is 5\ units

Third step: Move 5\ units  to the right. Observe that the distance between the numbers 13  and  8 is 5\ units

You can also verify this through the following addition and subtraction:

8-5=3\\\\\\8+5=13

Therefore, the numbers that are a distance of 5\ units  from  8 on a number line, are:

 3 and 13

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