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4 years ago

Somebody help me!!!!!!!!!!!!!!!!!!!!! (Geometry)

Mathematics

2 answers:

Alborosie4 years ago

7 0

Hello!

You can make a proportion

$\frac{3}{5} = \frac{36}{x}$

Cross multiply

36 × 5 = 180

Divide by 3

180 ÷ 3 = 60

$\framebox {60 feet}$

Svetlanka [38]4 years ago

3 0

Use similar triangles to solve this. 3 is to 36 as 5 is to x. Setting that up as a proportion gives us $\frac{3}{36}= \frac{5}{x}$ . Cross-multiply to get 3x=180. That means that the length of the ladder has to be 60 feet long to be safe.

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Max wants to run 512 miles to train for track season. If the total length around the track is

GalinKa [24]

Max needs to run 15 laps around the track.

Step-by-step explanation:

Given,

Distance Max wants to run = 512 miles

Length around the track = 34 mile

34 miles = 1 lap

1 mile = $\frac{1}{34}\ laps$

512 miles = $\frac{1}{34}*512$

512 miles = 15.06 laps

Rounding off to nearest whole number;

512 miles = 15 laps

Max needs to run 15 laps around the track.

Keywords: unit rate, division

Learn more about division at:

#LearnwithBrainly

4 0

3 years ago

This is hard broooooooooo

timofeeve [1]

Thes answer would be 51 or -51

6 0

3 years ago

Read 2 more answers

It S.P. =Rs810, loss percent=10% find C.p

zlopas [31]

Answer:

x=900

Step-by-step explanation:

100-10=90

90/100=0.9

x*0.9=810

x=810/0.9

<em>x=900:)</em>

hope it helps!!

Have a great day

5 0

3 years ago

Use multiplying by 1 to find an expression equivalent to 3/14 with a denominator of 14 y.

Soloha48 [4]

As a matter of simplification, same/same = 1.

now, "same" could be anything whatsoever, you name it, a whole polynomial, a whole anything whatsoever.

$\bf \cfrac{\sqrt{2}}{\sqrt{2}}=\cfrac{\sqrt{3}}{\sqrt{3}}=\cfrac{100000000}{100000000}=\cfrac{eggs}{eggs}=\cfrac{miles}{miles}=\cfrac{\frac{\quad \sqrt{3}}{\sqrt[5]{17}}\quad }{\frac{\sqrt{3}}{\sqrt[5]{17}}}=\cfrac{whatever}{whatever}=1$

now, that said, let us use 1 in this case then ... hmmmm we simply need a "y" in the denominator, so we simply multiply the denominator AND numerator by "y", y/y = 1 btw.

$\bf \cfrac{3}{14}\cdot \cfrac{y}{y}\implies \cfrac{3y}{14y}$

6 0

4 years ago

A cake is removed from a 310°F oven and placed on a cooling rack in a 72°F room. After 30 minutes the cake's temperature is 220°

Fynjy0 [20]

Answer:

The time is 135 min.

Step-by-step explanation:

For this situation we are going to use Newton's Law of Cooling.

Newton’s Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the surrounding medium and is given by

$T(t)=C+(T_0-C)e^{kt}$

where,

C = surrounding temp

$T(t)$ = temp at any given time

t = time

$T_0$ = initial temp of the heated object

k = constant

From the information given we know that:

Initial temp of the cake is 310 °F.
The surrounding temp is 72 °F.
After 30 minutes the cake's temperature is 220 °F.

We want to find the time, in minutes, since the cake's removal from the oven, at which its temperature will be 100°F.

To do this, first, we need to find the value of k.

Using the information given,

$220=72+(310-72)e^{k\cdot 30}\\\\72+238e^{k30}=220\\\\238e^{k30}=148\\\\e^{k30}=\frac{74}{119}\\\\\ln \left(e^{k\cdot \:30}\right)=\ln \left(\frac{74}{119}\right)\\\\k\cdot \:30=\ln \left(\frac{74}{119}\right)\\\\k=\frac{\ln \left(\frac{74}{119}\right)}{30}$

$T(t)=72+(310-72)e^{(\frac{\ln \left(\frac{74}{119}\right)}{30}\cdot t)}$

Next, we find the time at which the cake's temperature will be 100°F.

$100=72+(310-72)e^{(\frac{\ln \left(\frac{74}{119}\right)}{30}\cdot t)}\\72+238e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=100\\238e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=28\\e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=\frac{2}{17}\\\ln \left(e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}\right)=\ln \left(\frac{2}{17}\right)\\\frac{\ln \left(\frac{74}{119}\right)}{30}t=\ln \left(\frac{2}{17}\right)\\t=\frac{30\ln \left(\frac{2}{17}\right)}{\ln \left(\frac{74}{119}\right)}\approx 135.1$

4 0

3 years ago