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Tamiku [17]
2 years ago
6

A math book costs $9 and a science book costs $7. If Steve spends all his money in the science books, he still has $6 left. Howe

ver, if he buys the same number of math books, he needs another $8 more.
A. How much books is Steve buying?
B. How much money does he have?
Mathematics
2 answers:
Keith_Richards [23]2 years ago
5 0
A. 7 books each
B. he has $55
crimeas [40]2 years ago
5 0

Answer:

Step-by-step explanation:

Let <u>M</u> and <u>S</u> be the numbers of Math and Science books, respectively.  Let <u>T</u> be Steve's Total money he has to play with.

We are told that if Steve splurges (as he should) on nothing but science books. he has $6 left.

We can write this as:  <u>7S = T - 6</u>  [The number of science books, S, times $7 each, leaves Steve with only $6 (T - 6).]

We also find that if he buys the same number of math books, he'll need $8 more.  Zounds.  But we can write this as:  <u>9M = T + 8</u>  But since we know he is buying the same number as science, we can also write this as <u>9S = T + 8    </u>[The same number as he bought for science, S, times $9, Steve needs another $8].

We have two equations and two unknows (S and T), so lets see if we can solve for these variables.

7S = T - 6

9S = T + 8

Let's rearrange the first:  T = 7S + 6

Now use that  vale of T in the second equation:  

9S = T + 8

9S = (7S + 6) + 8

2S = 14

S = 7  That's 7 Science books.  It's also the value of M, 7 math books, since the problem states <u>if</u> he bought the same number as science books.

Now use S = 7 to find T, the total money Steve has [after coffee and doughnuts].

7S = T - 6

7*7 = T - 6

T = 49 + 6

T = $55

----

Let's see if $55 works for both the science and math book options:

1.  7 Science books:  $7/(S book)*(7 books) = $49  [He has $6 left]

2.  7 Math books:  $9/(M book)*(7 books) = $63  [He needs $8 more]

These results match the problem statements.

Steve has $55 (T).  He can buy either  7 science books or 6 math books:

Math:  6*($9) = $54  with $1 left, or

Science:  7*($7) = $49 with $6 left.

I suggest 6 Science books ($42) and 1 Math book ($9) for a total of $51, and still have $3 for coffee.  We aren't told if these books are all different from one another.  If they aren't, then Steve needs to ponder why he needs duplicated books.

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Answer:

1- The solution of I2x + 5I = 9 is {-7 , 2}

2- The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- The solution of I5 - xI = 6 is {-1 , 11}

4- The solution of I6x - 8I + 7 = 5 is ∅

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Step-by-step explanation:

* At first lets explain the meaning of IxI = a

- If IxI = a ⇒ then x = a or x = -a

- IxI never give a negative answer, because IxI means the

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Ex: I-2I is 2

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1- ∵ I2x + 5I = 9

∴ 2x + 5 = 9 ⇒ subtract 5 from both sides

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OR

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* The solution of I2x + 7I + 2 = 11 is {-8 , 1}

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∴ 5 -x = -6 ⇒ subtract 5 from both sides

∴ -x = -11 ⇒ divide both sides by -1

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* The solution of I5 - xI = 6 is {-1 , 11}

4- ∵ I6x - 8I + 7 = 5 ⇒ Subtract 7 from both sides

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- I  I never give negative answer

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OR

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∴ x = -15

* The solution of Ix + 3I = 12 is {-15 , 9}

6- ∵ Ix - 3I = -12

- I  I never give negative answer

* The solution of Ix - 3I = -12 is ∅

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