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77julia77 [94]
3 years ago
6

Please help! sort the equations by whether they are polynomial or not (picture attached)

Mathematics
1 answer:
AveGali [126]3 years ago
4 0

Answer:

The ones with the square root and fractions are not polynomials and the one with the negative powers and the x^2+3x^5-6x+12x^3 are not polynomials. The rest are.

Step-by-step explanation:

If this has helped you, please mark brainliest. I can explain if you want, let me know in comments.

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17 calculators for 340$ or 200 calculators for 3,600.
solong [7]
The better deal is the 200 calculators
3 0
3 years ago
Learning Task 1: Illustrate the following fractions on your notebook.
Marizza181 [45]

Answer:

The illustration is found in the attachment below.

<em>Note: The correct order of the question is found below:</em>

<em>Learning Task 1: Illustrate the following fractions on your notebook.</em>

<em>a.)2/3 b.)7/9 c.)10/12 d.)8/12 e.)4/5 f.) 8/6 g.)9/4 h.) 28/10</em>

Step-by-step explanation:

a) Draw a rectangle of sides 3 cm by 1 cm. Divide the rectangle into three equal parts. Shade two out of the three parts to give the fraction 2/3

b)  Draw a rectangle of sides 9 cm by 1 cm. Divide the rectangle into nine equal parts. Shade seven out of the nine parts to give the fraction 7/9

c)  Draw a rectangle of sides 12 cm by 1 cm. Divide the rectangle into twelve equal parts. Shade ten out of the twelve parts to give the fraction 10/12

d)  Draw a rectangle of sides 12 cm by 1 cm. Divide the rectangle into twelve equal parts. Shade eight out of the twelve parts to give the fraction 8/12

e)  Draw a rectangle of sides 5 cm by 1 cm. Divide the rectangle into five equal parts. Shade four out of the five parts to give the fraction 4/5

f)  Draw two rectangle of sides 6 cm by 1 cm. Divide the rectangles into six equal parts each. Shade all the six parts of the first rectangle completely. Then, shade two out of the six parts of the second rectangle to give the fraction 8/6

g) Draw three rectangles of side 4 cm by 1 cm. Divide each of the three rectangles into four parts each. Shade completely the four parts of the first and second rectangle. Then, shade one part out of the four parts of the third rectangle to give the fraction 9/4

h) Draw three rectangles of side 10 cm by 1 cm. Divide each of the three rectangles into ten parts each. Shade completely the ten parts of the first and second rectangle. Then, shade eight parts out of the ten parts of the third rectangle to give the fraction 28/10

6 0
3 years ago
Subtract. Write your answer as a fraction in simplest form. 3/8−(−1/8)=
weqwewe [10]

Answer:

1/2

Step-by-step explanation:

3/8 + 1/8=

4/8=

1/2

6 0
3 years ago
The ground-state wave function for a particle confined to a one-dimensional box of length L is Ψ=(2/L)^1/2 Sin(πx/L). Suppose th
Hitman42 [59]

Answer:

(a) 4.98x10⁻⁵

(b) 7.89x10⁻⁶

(c) 1.89x10⁻⁴

(d) 0.5

(e) 2.9x10⁻²  

Step-by-step explanation:  

The probability (P) to find the particle is given by:

P=\int_{x_{1}}^{x_{2}}(\Psi\cdot \Psi) dx = \int_{x_{1}}^{x_{2}} ((2/L)^{1/2} Sin(\pi x/L))^{2}dx  

P = \int_{x_{1}}^{x_{2}} (2/L) Sin^{2}(\pi x/L)dx     (1)

The solution of the intregral of equation (1) is:

P=\frac{2}{L} [\frac{X}{2} - \frac{Sin(2\pi x/L)}{4\pi /L}]|_{x_{1}}^{x_{2}}  

(a) The probability to find the particle between x = 4.95 nm and 5.05 nm is:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{4.95}^{5.05} = 4.98 \cdot 10^{-5}    

(b) The probability to find the particle between x = 1.95 nm and 2.05 nm is:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{1.95}^{2.05} = 7.89 \cdot 10^{-6}  

(c) The probability to find the particle between x = 9.90 nm and 10.00 nm is:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{9.90}^{10.00} = 1.89 \cdot 10^{-4}    

(d) The probability to find the particle in the right half of the box, that is to say, between x = 0 nm and 50 nm is:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5

(e) The probability to find the particle in the central third of the box, that is to say, between x = 0 nm and 100/6 nm is:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{16.7} = 2.9 \cdot 10^{-2}

I hope it helps you!

3 0
4 years ago
Write an equation of the line that passes through the points (-2, -3) and (1, -3)._____________ What is the slope?___
Gre4nikov [31]

Answer:

y = -3, slope = 0

Step-by-step explanation:

1) First, find the slope of the line. Substitute the x and y values of the given points into the slope formula, m  = \frac{y_2-y_1}{x_2-x_1}, and solve:

m = \frac{(-3)-(-3)}{(1)-(-2)} \\m = \frac{-3+3}{1+3} \\m = \frac{0}{4} \\m = 0

Thus, the slope is 0.

2) If a line has a slope of 0, that means it is horizontal. All horizontal lines are represented by the equation y = a number. That number is determined by the y-value of all the points the line intersects. Thus, find the y-value of the given points and put it into the equation. Looking at the given points, that number would be -3, so y = -3 is the equation.

3 0
3 years ago
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