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Alenkasestr [34]
3 years ago
12

Given that x is a whole number, Molly conjectured that x3>3x+3 . Which value is a counterexample to Molly's conjecture?\

Mathematics
2 answers:
stealth61 [152]3 years ago
5 0
C. 2 ............................

sleet_krkn [62]3 years ago
4 0
Ur counter example would mean making that conjecture false.

x^3 > 3x + 3....subbing in 2
2^3 > 3(2) + 3
8 > 6 + 3
8 > 9....this is not true...so ur answer is C. 2
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Makayla is moving and must rent a truck. There is an initial charge of $40 for the rental plus a fee of $3 per mile driven. Writ
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Qual é o mdc de 340 e 728?
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3 years ago
In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

7 0
3 years ago
Cartoon=uuu
LekaFEV [45]

Answer:

three u's and an I

Step-by-step explanation:

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8 0
3 years ago
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