All categories

3 years ago

At what position on the number line is the red dot located?

Mathematics

2 answers:

Naddika [18.5K]3 years ago

8 0

The answer would be d. √13 (square root of thirteen)

i hope this helps!!

AleksandrR [38]3 years ago

6 0

The answer should be D. the sqrt of 13

You might be interested in

Find the difference (4ab-9a-8)-(7ab-1)

OLga [1]

(4ab - 9a - 8) - (7ab - 1)
distribute (multiply) the negative through the parenthesis
(4ab - 9a - 8) - 7ab + 1
No need for other parenthesis because nothing in front or to combine inside. 
4ab - 9a - 8 - 7ab + 1 
Combine like terms
- 3ab - 9a - 7

7 0

3 years ago

What is the value of X

erica [24]

Answer:

x=3

Step-by-step explanation:

the sides MJ and MK should be equal so 12x-24 = 4x

if you isolate x you get 3

3 0

3 years ago

Read 2 more answers

Solve to find x. 7x - 12 = x - 6

Annette [7]

Hi,

7x - x = - 6 + 12

6x = 6

x = 6/6 = 1

3 0

3 years ago

A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

7 0

2 years ago

At midnight the temperature was -8 degree F. At noon the Temperature was 23 degrees F. Which expression represents the increase

Firlakuza [10]

23- -8

This equals to 31. 31 degrees was the increase

6 0

3 years ago