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Nady [450]
3 years ago
6

At what position on the number line is the red dot located?

Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0
The answer would be d. √13 (square root of thirteen)

i hope this helps!!
AleksandrR [38]3 years ago
6 0

The answer should be D. the sqrt of 13

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Question in pic pls help
krek1111 [17]
Linear not sure ...........
6 0
2 years ago
Original price =282$ %Markdown =10%
EleoNora [17]

Answer:

Markdown is a reduction in the price of a product, made either by a commercial promotion, by a limited-time offer, by a discount due to a failure in the product, or any other situation that implies the realization of said reduction in the final price of the product for sale.

Thus, if the original price of the product is $282, and it has a markdown of 10%, to determine the discounted amount and the final price of the product, the following calculation must be made:

282 x 0.10 = X

28.2 = X

Thus, the discount on the original price is $ 28.20. Therefore, the final sale price will be $ 253.80 (since 282 - 28.20 is equal to that number).

6 0
3 years ago
Please help me it’s emergency please
Lostsunrise [7]

Answer:

1.012 \times {10}^{ - 4}

Step-by-step explanation:

move the decimal so there is one non-zero digit to the left of the decimal point. the number of decimal places you move will be the exponent on the 10. if the decimal is being moved to the right, the exponent will be negative. if the decimal is being moved to the left, the exponent will be positive.

6 0
3 years ago
Read 2 more answers
What percentage of babies born in the United States are classified as having a low birthweight (<2500g)? explain how you got
lawyer [7]

Answer:

2.28% of babies born in the United States having a low birth weight.

Step-by-step explanation:

<u>The complete question is</u>: In the United States, birth weights of newborn babies are approximately normally distributed with a mean of μ = 3,500 g and a standard deviation of σ = 500 g. What percent of babies born in the United States are classified as having a low birth weight (< 2,500 g)? Explain how you got your answer.

We are given that in the United States, birth weights of newborn babies are approximately normally distributed with a mean of μ = 3,500 g and a standard deviation of σ = 500 g.

Let X = <u><em>birth weights of newborn babies</em></u>

The z-score probability distribution for the normal distribution is given by;

                          Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 3,500 g

            \sigma = standard deviation = 500 g

So, X ~ N(\mu=3500, \sigma^{2} = 500)

Now, the percent of babies born in the United States having a low birth weight is given by = P(X < 2500 mg)

         

   P(X < 2500 mg) = P( \frac{X-\mu}{\sigma} < \frac{2500-3500}{500} ) = P(Z < -2) = 1 - P(Z \leq 2)

                                                                 = 1 - 0.97725 = 0.02275 or 2.28%

The above probability is calculated by looking at the value of x = 2 in the z table which has an area of 0.97725.

4 0
3 years ago
Only 6 I need need serious help
k0ka [10]

Answer:

100,000+60,000+60

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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