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Nady [450]
3 years ago
6

At what position on the number line is the red dot located?

Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0
The answer would be d. √13 (square root of thirteen)

i hope this helps!!
AleksandrR [38]3 years ago
6 0

The answer should be D. the sqrt of 13

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Pls answer also no explanation no brainliest.
soldier1979 [14.2K]

Answer:

i belive the answer is the option c

3 0
3 years ago
Read 2 more answers
M
Olegator [25]

Answer:

the answer is B

Step-by-step explanation:

4 0
3 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Tomtit [17]

Apparently my answer was unclear the first time?

The flux of <em>F</em> across <em>S</em> is given by the surface integral,

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S

Parameterize <em>S</em> by the vector-valued function <em>r</em>(<em>u</em>, <em>v</em>) defined by

\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k

with 0 ≤ <em>u</em> ≤ π/2 and 0 ≤ <em>v</em> ≤ π/2. Then the surface element is

d<em>S</em> = <em>n</em> • d<em>S</em>

where <em>n</em> is the normal vector to the surface. Take it to be

\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}

The surface element reduces to

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\implies\mathbf n\,\mathrm dS=-49(\cos u\sin^2v\,\mathbf i+\sin u\sin^2v\,\mathbf j+\cos v\sin v\,\mathbf k)\,\mathrm du\,\mathrm dv

so that it points toward the origin at any point on <em>S</em>.

Then the integral with respect to <em>u</em> and <em>v</em> is

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S=\int_0^{\pi/2}\int_0^{\pi/2}\mathbf F(x(u,v),y(u,v),z(u,v))\cdot\mathbf n\,\mathrm dS

=\displaystyle-49\int_0^{\pi/2}\int_0^{\pi/2}(7\cos u\sin v\,\mathbf i-7\cos v\,\mathbf j+7\sin u\sin v\,\mathbf )\cdot\mathbf n\,\mathrm dS

=-343\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}\cos^2u\sin^3v\,\mathrm du\,\mathrm dv=\boxed{-\frac{343\pi}6}

4 0
3 years ago
7. The largest of the Great Pyramids in Egypt was built with a square base,
strojnjashka [21]

Answer:

Difference between the original and current volumes = 4013140.30 cubic feet

Step-by-step explanation:

Largest pyramid has the square base with one edge = 754 feet

Area of the square base = (Side)²

                            = (754)²

                            = 568516 square feet

Volume of the pyramid = \frac{1}{3}(\text{Area of the base})(\text{Height})

                                       = \frac{1}{3}\times 568516\times 481

                                       = 91152065.3 cubic feet

After erosion,

Area of the base = (745)² = 555025 square feet

Volume of the pyramid = \frac{1}{3}(555025)(471)

                                       = 87138925 cubic feet

Difference between the original and current volumes of the pyramid

= 91152065.30 - 87138925

= 4013140.30 cubic feet

5 0
3 years ago
Five classes collected money for a charity of their choice. The amounts of money collected by the boys and girls of each are sho
34kurt

The girls collected 8.5 pounds more than the boys in class 4

<h3>Complete question</h3>

Five classes collected money for a charity of their choice. The amounts of money collected by the boys and girls of each are shown in the chart below.

In Class 4, how much more money did the girls collect than the boys?

<h3>How to determine the difference in amounts?</h3>

From the attached chart, we have the following amount in class 4:

Girls = 12 pounds

Boys = 3.5 pounds

The difference is calculated as:

Difference = Girls - Boys

So, we have:

Difference = 12 pounds - 3.5 pounds

Evaluate

Difference = 8.5 pounds

Hence, the girls collected 8.5 pounds more than the boys in class 4

Read more about charts at:

brainly.com/question/25583717

#SPJ1

8 0
1 year ago
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