Solve your equation step-by-step.
x^2+5=41
Subtract 5 from both sides.
x^2+5−5=41−5
x^2=36
Take square root.
x=±√36
x=6
or
x=−6
So your answer suppose to be C and D.
But if you were to put only one answer in the answering box, then just say C)
To figure out the answer to this problem, you need to divide the amount of feet Ann ran by the amount of total feet that Ann covered.
1320/5280 is your fraction.
If you simplify this fraction, you get 1/4, which is 0.25 or 25% of the mile.
Answer:
S₁₅ = 127.5
Step-by-step explanation:
the nth term of an arithmetic progression is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
given a₃ = 1 and a₇ = 7 , then
a₁ + 2d = 1 → (1)
a₁ + 6d = 7 → (2)
subtract (1) from (2) term by term to eliminate a₁
0 + 4d = 6
4d = 6 ( divide both sides by 4 )
d = 1.5
substitute d = 1.5 into (1) and solve for a₁
a₁ + 2(1.5) = 1
a₁ + 3 = 1 ( subtract 3 from both sides )
a₁ = - 2
the sum to n terms of an arithmetic progression is
= 
[ 2a₁ + (n - 1)d ]
with a₁ = - 2 and d = 1.5 , then
S₁₅ = 
[ (2 × - 2) + (14 × 1.5) ]
= 7.5(- 4 + 21)
= 7.5 × 17
= 127.5
Answer:
Step-by-step explanation:
1. There will be 9 roses in total.
Probability Orange: 2/9
Probability Yellow: 3/9 = ⅓
Probability Pink: 4/9
2. 4/7 as there are 7 bowls in total and 4 are chocolate.
3. 4/10 = ⅖ (simplified) There are 10 fruits in total and 4 are apples.
4. 5/15 = ⅓ (simplified) There are 15 cars in total and 5 or them are cooper minis.
5. 2/6 = ⅓ (simplified) There are 6 textbooks and 2 of them are math.
6. 13/20 There are 20 drinks and 13 of them are lemonade.
7. There are 10 toys in total.
Probability toy cars: 3/10
Probability dolls: 2/10 = ⅕ (simplified)
Probability balls: 5/10 = ½ (simplified)
8. In total the number of red roses and lilies are 7. There are 10 flowers in total so the number of jasmines are 3. Therefore the probability of getting a jasmine is 3/10
9. 20/50 = ⅖ (simplified) There are 50 papers in total and 20 of them are yellow.
10. 8/18 = 4/9 (simplified) There are 18 buses and 8 of them are air conditioned.
