According to financial advisers,
<span>* mortgage payment should be at most </span><span>28% of your gross monthly income
</span><span>* total monthly debt should be at most </span><span>36% of your gross monthly income. Total monthly debts include </span><span>mortgage payments, car payments, credit card bills,
student loans, and medical debt.\</span>
<span>gross annual income: 39,600</span>
gross monthly income: 39,600 / 12 = 3,300
a) maximum amount for monthly mortgage payment: 3,300 x 28% = 924
b) maximum amount for total credit obligations: 3,300 x 36% = 1,188
c) mortgage: 924 x 70% = 646.80 actual mortgage
1,188 - 646.80 = 541.20 maximum amount they could spend each month for all other debts.
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Answer:
#1. Identity #2. 0 #3. No solution
Step-by-step explanation:
#1.
5y + 2 = (1/2)(10y+4)
5y + 2 = 5y + 2
This would be identity as the equation of the left and right are the same. This is not to be confused with no solution(explained below).
#2.
0.5b + 4 = 2(b+2)
0.5b + 4 = 2b + 4
0.5 b - 2b = 0
b = 0
#3.
-3x + 5 = -3x + 10
This equation has no solution because when you try to bring the -3x to one side, the x variable itself gets eliminated. So, how is it different from identity? Well in the first equation, it is true that when we try to bring the 5y one side it eliminates the y variable, however, that is also true for the constants(since if we try to bring the 2 to one side, it will be 2-2 which will equal 0, thus eliminating each other), but in this case, even if we remove the x, the constants will not equal 0, thus it will have no solution.
Answer:
I think the answer is B
Explanation:
1.25x10 to the power of 7 =
12,500,000
I hope it helps!
Answer:
(2a, 2b)
Step-by-step explanation:
(0, 2b)
(2a, 0)
(2a, 2b)
I racked my brain for that.
Answer:
Step-by-step explanation:
Given that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective.
Probability for any one to be defective as of now is 
a) 
b) After I draw we have 35 good ones and 9 defective
P(F/E) =
c) P(G/EF)
This is the probability for iii bulb to be good given I and II are goog.
Once I and ii are good we have 43 bulbs with 34 good ones
