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Vladimir [108]
3 years ago
13

Pls take a look at the picture! It should be easy if you know radicals.

Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

Answer:

The answer is 2√15 .

Step-by-step explanation:

Using Indices Law :

\sqrt{a}  \times  \sqrt{b}  =  \sqrt{ab}

\sqrt{ - 6}  \times  \sqrt{ - 10}

=  \sqrt{ - 6 \times  - 10}

=  \sqrt{60}

Next, you have to find the common factors of 60 :

60 = 1×60

60 = 2×30

60 = 3×20

60 = 4×15

60 = 5×12

60 = 6×10

In order to simplify, we have to choose a perfect square from the factors above. In the factors above, 4 is a perfect square so that we can square root it :

\sqrt{60}

=  \sqrt{4 \times 15}

=  \sqrt{4}  \times  \sqrt{15}

= 2 \times  \sqrt{15}

= 2 \sqrt{15}

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A jar contains 1,200 M&M's and everyday your family eats 1/5th of the candies. After how many days will there be 314 M&M
mrs_skeptik [129]
The equation is 314 = 1,200 - 240x

1,200 is the number of M&M's it starts with
The problem said the family eats 1/5th of the candy every day
1/5 of 1,200 is 240
It is a -240 because the amount of m&m's is getting fewer each day
The x stands for the number of days

Sorry but I'm not sure if I could answer your problem exactly
The answer is 3.69 days
Because there isn't an exact day that there would exactly 314 M&M's left

7 0
3 years ago
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Bumek [7]

Answer:

r=5.8

Step-by-step explanation:

Just do 17.4 divided by 3

And you get R

Hope this helps!

6 0
3 years ago
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Sergio [31]

Answer:

I would say it is line Q. Because it goes down one and left one. Hope this helps

Step-by-step explanation:

8 0
3 years ago
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miskamm [114]
-11+square root of 19/ 20   ,     -11- square root of 19/ 20
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3 years ago
ASAP!!!!!!!!!!!!!!!!!! Consider the point A=(1,3) and the line B, given by the equation y=2x-2 write an equation in slope-interc
vagabundo [1.1K]

Answer:

y = 2x+1 (slope-intercept form)

Step-by-step explanation:

From line B, y = 2x -2 and comparing with the general equation of line, y = mx +c, we have

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Parallelism rule states that m1=m2

Therefore, m2 = 2

Hence, the equation passing through point A(1,3) is

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8 0
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