All categories

3 years ago

Which of the following is a monomial?

Mathematics

1 answer:

MAXImum [283]3 years ago

6 0

A monomial has one term, even if it has multiple variables.
So your answer would be A. 2xyz2. Hope it helps! :)

You might be interested in

A store sells small notebooks for $6 and large notebooks for $10. If a student buys 6 notebooks and spends $52, how many of

NISA [10]

Answer:

you can say he bought 2 small notebooks and 4 big notebooks

Step-by-step explanation:

we have 52 dollars here

so if we have 4 large notebooks that will cost 40 dollars and if we have 2 small notebooks on addiction to that, that will cost 12 more dollars

now adding up 40 and 12 we get $52 !

3 0

2 years ago

Find the area of the triangle.<br> 24 in.<br> 32 in.

mrs_skeptik [129]

Answer:

A = 384 inches^2

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh where b is the length of the base and h is the height

A = 1/2 ( 32) *(24)

A = 384 inches^2

7 0

3 years ago

Read 2 more answers

How many square feet of outdoor carpet will we need for this hole??? ANSWER QUICKLY

mario62 [17]

I guess so 35 ft or more than it

6 0

3 years ago

Your dad is designing a new garden for your backyard. He has 20 feet of fencing to go around the garden. He wants the length of

Komok [63]

Answer:

Length = 6.25 feet

Step-by-step explanation:

Your dad is designing a new garden for your backyard. He has 20 feet of fencing to go around the garden.

Let the width is x.

Length is 2 1/2 feet longer than the width i.e. (x+2 1/2) = (x+2.5) feet

Perimeter = 20 feet

2(l+b) = 20

(l+b) = 10

(x+2.5+x) = 10

2x+2.5 = 10

2x = 7.5

x = 3.75 feet

Length = (x+2.5)

= (3.75+2.5)

= 6.25 feet

So, the length of the garden is 6.25 feet.

3 0

3 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

2 years ago