1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
PolarNik [594]
2 years ago
11

Picky Polls asked 1600 third-year college students if they still had their original major. According to the colleges, 50% of all

third-year college students still had their original major. Picky Polls got less than 800 students who said they still had their original major. How likely is this result? Assume the normal model applies here. You may use your calculator or reference the z tables when working with normal models.

Mathematics
1 answer:
Reptile [31]2 years ago
7 0

Answer:

The probability that less than 800 students who said they still had their original major is 0.50 or 50%.

Step-by-step explanation:

Let the random variable <em>X</em> be described as the number of third-year college students if they still had their original major.

The probability of the random variable <em>X</em> is, P (X) = <em>p</em> = 0.50.

The sample selected consisted of <em>n</em> = 1600 third-year college students.

The random variable <em>X </em>thus follows Binomial distribution with parameters n = 1600 and p = 0.50.

X\sim Bin(1600, 0.50)

As the sample size is large, i.e.<em>n</em> > 30, and the probability of success is closer to 0.50,  Normal approximation can be used to approximate the binomial distribution.

The mean of <em>X</em> is:

\mu_{x}=np=1600\times0.50=800\\

The standard deviation of <em>X</em> is:

\sigma_{x}=\sqrt{np(1-p}=\sqrt{1600\times0.50(1-0.50)}=20

It is provided that Picky Polls got less than 800 students who said they still had their original major.

Then the probability of this event is:

P(X

**Use the <em>z</em>-table for the probability.

Thus, the probability that less than 800 students who said they still had their original major is 0.50.

You might be interested in
Compute the line integral with respect to arc length of the function f(x, y, z) = xy2 along the parametrized curve that is the l
SIZIF [17.4K]

Answer:

\displaystyle\frac{15\sqrt{3}}{4}-90\sqrt{146}

Step-by-step explanation:

The line integral with respect to arc length of the function f(x, y, z) = xy2 along the parametrized curve that is the line segment from (1, 1, 1) to (2, 2, 2) followed by the line segment from (2, 2, 2) to (−9, 6, 5) equals the sum of the line integral of f along each path separately.

Let  

C_1,C_2  

be the two paths.

Recall that if we parametrize a path C as (r_1(t),r_2(t),r_3(t)) with the parameter t varying on some interval [a,b], then the line integral with respect to arc length of a function f is

\displaystyle\int_{C}f(x,y,z)ds=\displaystyle\int_{a}^{b}f(r_1,r_2,r_3)\sqrt{(r'_1)^2+(r'_2)^2+(r'_3)^2}dt

Given any two points P, Q we can parametrize the line segment from P to Q as

r(t) = tQ + (1-t)P with 0≤ t≤ 1

The parametrization of the line segment from (1,1,1) to (2,2,2) is

r(t) = t(2,2,2) + (1-t)(1,1,1) = (1+t, 1+t, 1+t)

r'(t) = (1,1,1)

and  

\displaystyle\int_{C_1}f(x,y,z)ds=\displaystyle\int_{0}^{1}f(1+t,1+t,1+t)\sqrt{3}dt=\\\\=\sqrt{3}\displaystyle\int_{0}^{1}(1+t)(1+t)^2dt=\sqrt{3}\displaystyle\int_{0}^{1}(1+t)^3dt=\displaystyle\frac{15\sqrt{3}}{4}

The parametrization of the line segment from (2,2,2) to  

(-9,6,5) is

r(t) = t(-9,6,5) + (1-t)(2,2,2) = (2-11t, 2+4t, 2+3t)  

r'(t) = (-11,4,3)

and  

\displaystyle\int_{C_2}f(x,y,z)ds=\displaystyle\int_{0}^{1}f(2-11t,2+4t,2+3t)\sqrt{146}dt=\\\\=\sqrt{146}\displaystyle\int_{0}^{1}(2-11t)(2+4t)^2dt=-90\sqrt{146}

Hence

\displaystyle\int_{C}f(x,y,z)ds=\displaystyle\int_{C_1}f(x,y,z)ds+\displaystyle\int_{C_2}f(x,y,z)ds=\\\\=\boxed{\displaystyle\frac{15\sqrt{3}}{4}-90\sqrt{146}}

8 0
3 years ago
3 over 8 plus 2 over 3 plus 1 over 3
wariber [46]
3 over 8 plus 2 over 3 plus 1 over 3 =  11 over 8 or 1.375
4 0
3 years ago
Read 2 more answers
Can some also explain it to me how to identify if it’s continuous exponential
sweet-ann [11.9K]
B is the correct answer


hope this helps
8 0
3 years ago
Convert 80 km per hour and 120 km per hour to meters per second​
Burka [1]

hi brainly user! ૮₍ ˃ ⤙ ˂ ₎ა

⊱┈────────────────────────┈⊰

\large \bold {ANSWER}

  • \large \boxed { \large \sf \green{ 80 km/h = 22.22 m/s }}
  • \large \boxed { \large \sf \green{ 120 km/h = 33.33 m/s }}

\large \bold {SOLUTION}

The first thing we must do is convert kilometers to meters. We will do this by multiplying by 1,000, since 1 km corresponds to 1,000 meters.

  • 80*1000 = 80,000
  • 120*1000 = 120,000

Now that we've done that, let's divide the values by 3,600, because an hour is 60 minutes, and each minute is 60 seconds, so 60*60 is 3,600.

\frac{80.0\not0\not0}{3.6\not0\not0}=22.22

\frac{120.0\not0\not0}{3.6\not0\not0}=33.33

Hence, 80 km/h = 22.22 m/s, 120 km/h = 33.33 m/s

8 0
1 year ago
Read 2 more answers
Which is an equation of the line that
Alex Ar [27]
Answer; D) y=-3x+13
4 0
3 years ago
Other questions:
  • Craig has 20 video games. Out of these 20 video games, 45% are sports games.
    9·1 answer
  • What is a descriptive adjective
    8·1 answer
  • Identify the independent and dependent variable:The equation t=12p+12 gives the total cost t (in dollars) of a meal with a tip o
    5·2 answers
  • Find the greatest common factor of 14, 20, and 25.
    14·1 answer
  • Thanks I have a pic or screenshot
    12·1 answer
  • I need help with the question above. I inserted a pic of the question. Can someone pls double check my answers are correct??
    10·2 answers
  • What are the roots of the quadratic equation below 2x ^ 2 - 12x + 13=0 PLEASE HELP
    11·1 answer
  • What is the first step to solve this equation:
    5·2 answers
  • 2
    12·1 answer
  • Need help with this number 3 and 4 all go together
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!