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3 years ago

Consider the triangles.

Mathematics

2 answers:

Bond [772]3 years ago

6 0

Answer:

i did this one i cant remeber what it was i think it was

Step-by-step explanation:

answer here

The corresponding angles are proportional.

if not then

The ratios of the corresponding sides are equivalent.

vlabodo [156]3 years ago

5 0

Answer:

BDE

Step-by-step explanation:

i just did it :)

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A recipe requires 3 cup of cornstarch. You can only measure using 1/4 cup. How many 1/4 cups are needed in the recipe

anastassius [24]

Answer:

Step-by-step explanation:

to make 1 cup with 1/4 cup you need to put 4.

therefore;

number of 1/4 cups needed = 3x4=12

7 0

2 years ago

Which of the following completes the rule for this translation, (x, y) → (x − 8, ___)?

almond37 [142]

Answer:

The answer would be c

Step-by-step explanation:

I did it edge yesterday

4 0

3 years ago

Read 2 more answers

Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

<em><u>Therefore, the two roots are:</u></em>

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago

Which of the following sets of possible side lengths does not form a triangle

Alex Ar [27]

Answer:

Step-by-step explanation:

In a triangle of sides‘s length a , b and c

in order to be able to form (construct) this triangle we must have :

c - a < b < c + a

in fact this work with cases a) ,c) and d)

but not b)

because 15 - 4 is not < to 5

in other words 15 - 4 > 5

3 0

3 years ago

What is the factorization of the polynomial below? -x^2-15x-54

amid [387]

To factor a polynomial we need to find 2 numbers that add up to -15 and multiply into -54.
(-x -18)(x +3) Will be your answer.

8 0

3 years ago