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iogann1982 [59]
3 years ago
13

-2/11 ÷ -3 /11 remember to simplify

Mathematics
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

\frac{2}{3}

Step-by-step explanation:

In math, when dividing by fractions, you need to multiply by the reciprocal.

-\frac{2}{11} *-\frac{11}{3}

Then, you can cross-cancel the 11

-\frac{2}{1}* -\frac{1}{3}

And multiply. Negatives cancel each other out so you get:

\frac{2}{3}

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What is a transformation that proportionally reduces or enlarges a figure.
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Step-by-step explanation:

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3 years ago
The maximum value of 12 sin 0-9 sin²0 is: -​
jeka57 [31]

Answer:

4

Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be \theta rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

f(\theta) = 12sin(\theta) - 9 sin^2(\theta)

Taking the first derivative of this with respect to \theta and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of f(\theta) w.r.t \theta is

                        12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right)

And setting this = 0 gives

12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0

Eliminating cos(\theta) on both sides and solving for sin(\theta) gives us

sin(\theta) = \frac{12}{18} = \frac{2}{3}

Plugging this value of sin(\theta) into the original equation gives us

12(\frac{2}{3}) - 9(\frac{4}{9} ) = 8 - 4 = 4

This is the maximum value that the function can acquire. The attached graph shows this as correct

3 0
2 years ago
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