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3 years ago

15

Using the GCF you found in Part B, rewrite 35 + 63 as two factors. One factor is the GCF and the other is the sum of two numbers

that do not have a common factor. Show your work. (4 points)

1 answer:

nikklg [1K]3 years ago

3 0

__7_|_35+63_
_____|__9+5__
35+63=7(9+5)=7<span>14=98 or 35+63=98</span>

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The two lines below intersect as shown What is the value of x?

Rufina [12.5K]

Answer:

x = 6

Step-by-step explanation:

because we know the lines intersect we also know the 2 angles are vertical meaning they are equal to each other

Knowing the angles are equal to each other you can make the equation

2x + 29 = 9x - 13

then you solve for x in this equation

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3 years ago

A store charges $280 for coat. This price is 40 percent more than the amount it cost the store to buy. At the end-of-season sale

NeX [460]

Let cost price be x
according to question
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this 200 is the store cost or cost price for store
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according to question,
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3 years ago

1/5 PART OF A POLE IS INSIDE THE MUD, 2/3 PART IS INSIDE THE WATER AND THE REMAINING LENGTH OF 10m IS ABOVE THE SURFACE OF THE W

Andrei [34K]

Answer:

1/ 5 and 2/3

cross multiple

example

1 2 = 10

/ x / = /

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so it's 3 1/3 + 10 Mm

so may guess is

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8 0

3 years ago

Read 2 more answers

No links! & help me please

melamori03 [73]

Answer:

150.72 units³

Step-by-step explanation:

The formula for solving the volume of a cylinder is:

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6 0

3 years ago

A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H

andrey2020 [161]

Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.3y\\
-----&-----&-------&-------\\
mixture&100&0.15&15
\end{array}
\\\\\\
\begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.3y=15\\
----------\\
0.5x+0.3\left( \boxed{100-x} \right)=15
\end{cases}$

solve for "x"

what's "y"? well, y = 100 - x

4 0

3 years ago