Question

The answer below thanks

Answer 1

Step-by-step explanation:

Let the center of the given circle be (h,k)

and its radius be 'r' units

Let (x,y) be a random point on the given circle

Now, distance between the points (x,y) and (h,k) will be equal to its radius, 'r'

$\sqrt{(x - h)^{2} + {(y - k)}^{2} } = r$

$\implies {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

$\implies {x}^{2} - 2xh + {h}^{2} + {y}^{2} - 2yk + {k}^{2} = {r}^{2}$

$\implies {x}^{2} + {y}^{2} - 2hx- 2ky + ( {h}^{2} + {k}^{2} - {r}^{2} ) = 0$

Here, is the required equation