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3 years ago

I dont know how to answer this 19=n/3-8

Mathematics

1 answer:

noname [10]3 years ago

4 0

Answer:

n = 81

Step-by-step explanation:

Isolate the variable, n. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First add, then multiply:

Add 8 to both sides:

19 = (n/3) - 8

19 (+8) = (n/3) - 8 (+8)

19 + 8 = n/3

n/3 = 27

Isolate the variable, n. Multiply 3 to both sides:

(n/3)(3) = (27)(3)

n = 27 * 3

n = 81

n = 81 is your answer.

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What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?

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Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

$AB = \sqrt{(11-4)^{2}+(3-3)^{2}}$

$AB = \sqrt{(7)^{2}+(0)^{2}}$

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As take B(11, 3) to C (11, 9).

$BC = \sqrt{(11-11)^{2}+(9-3)^{2}}$

$BC = \sqrt{(0)^{2}+(6)^{2}}$

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As take C (11, 9) toD (4, 9).

$CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}$

$CD = \sqrt{(7)^{2}+(0)^{2}}$

$CD = \sqrt{49}$

$\sqrt{49} =7$

CD = 7 units

As take D (4, 9) to A (4, 3)

$DA = \sqrt{(4-4)^{2}+(3-9)^{2}}$

$DA = \sqrt{(0)^{2}+(-6)^{2}}$

$DA = \sqrt{36}$

$\sqrt{36} =6$

DA = 6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value in the above

Area of rectangle = 7 × 6

= 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0

2 years ago

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