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Anna [14]
4 years ago
15

Which ordered pairs are solutions to the inequality 2x+y>−4?

Mathematics
1 answer:
alexgriva [62]4 years ago
4 0

Answer:

The ordered pairs are (5,-12), (-1,-1).

Step-by-step explanation:

Given : Inequality 2x+y>-4

To find : Which ordered pairs are solutions to the inequality ?

Solution :

We put the given options the point which satisfied the equation is the solution.

Inequality 2x+y>-4

1) (5,-12)

2(5)+(-12)>-4

10-12>-4

-2>-4

It is true.

2) (-1,-1)

2(-1)+(-1)>-4

-2-1>-4

-3>-4

It is true.

3) (-3,0)

2(-3)+(0)>-4

-6+0>-4

-6>-4

It is false.

4) (4,-12)

2(4)+(-12)>-4

8-12>-4

-4>-4

It is false.

Therefore, The ordered pairs are (5,-12), (-1,-1).

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Morgarella [4.7K]
Answer:
3 < c < 13
Step-by-step explanation:
A triangle is known to have 3 sides: Side a, Side b and Side c.
For a triangle, one of the three sides is longer than the other two sides. (The only exception is when we are told specifically that a triangle is an equilateral triangle, where all the 3 sides are equal to each other).
To solve the above question, we would be using the Triangle Inequality Theorem.
The Triangle Inequality Theorem states that the summation or addition of the lengths of any two sides of a triangle is greater than the length of the third side.
Side a + Side b > Side c
Side a + Side c > Side b
Side b + Side c > Side a
For the above question, we have 2 possible side lengths for the third side of the triangle. We are given in the above question,
side (a) = 5
side (b) = 8
Let's represent the third side as c
To solve for the above question,we would be having the following Inequality.
= b - a < c < b + a
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The answer is a
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