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schepotkina [342]
2 years ago
13

There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t

he quiz be selected if there must be at least three multiple choice questions selected?​
Mathematics
1 answer:
beks73 [17]2 years ago
3 0

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

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Solve for the unknown in the following diagram. Round the answer to two decimal places.<br>in<br>​
Alexxandr [17]

Answer:

172.27 in

Step-by-step explanation:

Apply the Sine Rule

Sine Rule is given as:

\frac{a}{sin(A)} = \frac{b}{sin(B)} = \frac{c}{sin(C)}

c = x = ?

C = 180 - (52 + 48) = 80° (sum of triangle)

b = 130 in.

B = 48°

Plug in the values

\frac{130}{sin(48)} = \frac{x}{sin(80)}

Multiply both sides by sin(80)

\frac{130*sin(80)}{sin(48)} = x

172.274641 = x

x = 172.27 in. (to 2 decimal places)

4 0
2 years ago
AB=AB=A, B, equals <br> 3.3<br> Round your answer to the nearest hundredth.
ad-work [718]
3.0? Im not sure but i this so
6 0
3 years ago
(25÷8)×219078%+2347910.Please show working on paper.Thanks.You will get 10 points.PLEASE HELP..
Elenna [48]
<span>2354756.1875
...............................</span>
7 0
3 years ago
Read 2 more answers
David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
2 years ago
Read 3 more answers
What is the absolute value of the distance from the numbers -6 to 5?
katovenus [111]

Answer: 11

Step-by-step explanation:

It is 11 because count from -6...

-6 = 0

-5 = 1

-4 = 2

-3 = 3

-2 = 4

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0 = 6

1 = 7

2 = 8

3 = 9

4 = 10

5 = 11

Hope this helpsand sorry if not

8 0
2 years ago
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