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nikdorinn [45]
3 years ago
9

Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applie

d on trapezoid STUV.
What will be the location of T' in the image trapezoid S'T'U'V'?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

The coordinates of T' will be T'(13,-1)

Step-by-step explanation:

step 1

Find the rule of the translation

take any point of rectangle JKLM (pre-image)

The coordinate of point k(-3,2)

The coordinate of point k'(4,7)

so

The rule of the transformation

k(-3,2) -----> k'(4,7)

is equal to

(x,y) ------> (x+7,y+5)

That means ----> the translation is 7 units at right and 5 units up

step 2

Apply the rule of the translation at the coordinate T of trapezoid STUV

we have

T(6,-6)

(x,y) ------> (x+7,y+5)

T(6,-6) ------> T'(6+7,-6+5)

T(6,-6) ------> T'(13,-1)

therefore

The coordinates of T' will be T'(13,-1)

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En una ciudad se registró una temperatura de 12°c bajo cero a las 3:00 am si a las 7:00am del mismo dia la temperatura era tres
hjlf

Answer:

24°c

Step-by-step explanation:

Cuando se dice que la temperatura esta "mayor" significaria que esta aumentando y entorno subiendo a ser mas caliente. Siendo este el caso, si la temperatura a las 3:00 estaba a 12c bajo cero entonces a las 7:00 estaria a 24c. Esto es por que un aumento de tres vecesseria un aumento de 36 grados (12*3). 12c grados bajo cero seria un numero negativo y si sumamos estos numeros nos daria 24c grados.

-12 + 36 = 24

7 0
3 years ago
What is the quotient 2 1/5 over negative 1/10​
valina [46]

Answer:

25

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The coordinates below represent two linear equations.
Alexxx [7]
So solve for the equations of the lines
y=mx+b
m=slope
b=y intercept

line 1=
(-4,5)
(0,2)
(x,y)
slope=(y1-y2)/(x1-x2)
x1=-4
y1=5
x2=0
y2=2
subsitute
(5-2)/(-4-0)=3/-4=-3/4
slope=-3/4
subsitute
y=-3/4x+b
subsitute one of the points
(0,2)
x=0 and y=2 is one solution
2=-3/4(0)+b
2=0+b
2=b
the equation is y=-3/4x+2



other line
(0,5)
(4,2)
x1=0
y1=5
x2=4
y2=2
sybsitute
(5-2)/(0-4)=3/-4=-3/4
slope=-3/4
subsitute
y=-3/4x+b
now subsitute one of the points to solve for b
(0,5)
x=0 and y=5 is one solution
5=-3/4(0)+b
5=0+b
5=b
y=-3/4x+5

so we have the lines/equations
y=-3/4x+2 and y=-3/4x+5
(at this point we can see that since slopes are the same and the y intercepts are different, they are paralell and therefor have 0 solutions, but for those who don't know paralellline thingie read on)

solve for  common (x,y)
y=-3/4x+2
y=-3/4x+5
subsitute
-3/4x+2=y=-3/4x+5
-3/4x+2=-3/4x+5
subtract 2 from both sides
-3/4x=-3/4x+5
add 3/4x to both sides
0=5
fasle
there are no solutions

the answer is A: 0 solutions
6 0
3 years ago
-5 divided by 1.5 show the work
Oxana [17]
It’s -3 repeating and there is the work your welcome child

6 0
3 years ago
Read 2 more answers
The radius, r, of a circle is one-half of the length of its diameter, d. r= r= d + r = d 2 r = d r = d
PIT_PIT [208]

If the radius is HALF of the diameter, then the expression would be 1/2r=d or d/2=r.

hope it helps!

8 0
3 years ago
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